All categories

3 years ago

What is the calue of the 9 in the number 914,566

Mathematics

2 answers:

loris [4]3 years ago

7 0

Nine hundred thousands place

choli [55]3 years ago

3 0

100,000, or hundred thousands place.

You might be interested in

What is the solution set?

rosijanka [135]

Step-by-step explanation:

$x \div 4 \leqslant 9 \div x$

$x ^{2} \leqslant 36$

$x {}^{2} - 36 \leqslant 0$

$x {}^{2} { - 6}^{2} \leqslant 0$

$(x + 6)(x - 6) \leqslant 0$

$x \leqslant - 6 \: \: or \: \: \: x \leqslant 6$

$- 6 \geqslant x \leqslant 6$

From the explanation the correct answer is the last one from the question above

8 0

3 years ago

Leena consumes 400 calories at breakfast and 350 calories at lunch. She consumes StartFraction 2 Over 3 EndFraction. of her dail

mr_godi [17]

Answer:

The first and second one

Step-by-step explanation:

Had the problem an it showed that those two were correct hope I help

6 0

3 years ago

Read 2 more answers

An aquarium has dimensions 2x feet, (x – 1) feet, and (x + 2) feet. The aquarium volume must be no more than 280 cubic feet.

Lina20 [59]

Answer:

$x^3+x^2-2x\leq140$

Step-by-step explanation:

This is an algebra problem, and we are expected to inequality for the volume of the aquarium.

Given that the

length= 2x

width=(x – 1)

heigth= (x + 2)

and the volume= 280 ft^3

the inequality expression for the volume is

$2x*(x -1) * (x + 2) \leq 280\\\\$

open the brackets

$2x*(x -1) * (x + 2) \leq 280\\\\(2x^2-2x)*(x+2)\leq 280\\\\\2x^3+4x^2-2x^2-4x\leq 280\\\\\2x^3+2x^2-4x\leq280$

divide through by 2 we have

$x^3+x^2-2x\leq140$

5 0

3 years ago

Read 2 more answers

if it would take billy an hour to race over to his girlfriends house and two hours if he went 20 miles per hour slower how far a

mel-nik [20]

Recall your d = rt, distance = rate * time.

now, let's say she lives "d" miles away, and so if Billy goes say at "r" mph fast to her house, he gets there in 1hr.

now, if he goes 20 mph slower, namely " r - 20 " mph, he gets there in 2 hours, same "d" miles.

$\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Billy}&d&r&1\\
\textit{slower Billy}&d&r-20&2
\end{array}
\\\\\\
\begin{cases}
d=r(1)\implies d=\boxed{r}\\
d=2(r-20)\\
----------\\
d=2\left( \boxed{d}-20 \right)
\end{cases}
\\\\\\
d=2d-40\implies 40=d$

5 0

3 years ago

A new Community Center is being built in Oak Valley. The perimeter of the rectangular playing field is 382 yards. The length of

vesna_86 [32]

Answer:

The width is 50 yards and the length is 141 yards.

Step-by-step explanation:

Let's call: L the length of the field and W the width of the field.

From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:

2L + 2W = 382

Because the perimeter of a rectangle is the sum of two times the length with two times the width.

Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:

L = 3W - 9

So, replacing this last equation on the first one and solving for W, we get:

2L + 2W = 382

2(3W - 9) + 2W = 382

6W -18 +2W = 382

8W - 18 = 382

8W = 382 + 18

8W = 400

W = 400/8

W = 50

Replacing W by 50 on the following equation, we get:

L = 3W - 9

L = 3(50) - 9

L = 141

So, the width of the rectangular field is 50 yards and the length is 141 yards.

3 0

3 years ago