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faust18 [17]
1 year ago
8

Match the polynomial expression on the left with the simplified version on the right.

Mathematics
1 answer:
Vitek1552 [10]1 year ago
3 0

Given the following question:

First expression:

\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}

Second expression:

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The sum of two numbers is 5.036. One number has a4 in the tenths place and a 7in the thousandths place. The other number has a 1
wlad13 [49]
The sum of two numbers 5.036.
first number: one number has 4 in the tenths place, 7 in the thousandths place.
=> x.4x7
2nd number: 1 in ones place and 2 in the hundredths place.
=> 1.x2x
Now, we have the 2 numbers with given clues:
=> x.4x7 + 1.x2x, where x is the missing number.
Note that in adding numbers, we start from the right most.
=>x.4x7 + 1.x2x = 5.036
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=> x.407 + 1.629
=> 3.407 + 1.629
=> 5.036



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3 years ago
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