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faust18 [17]
1 year ago
8

Match the polynomial expression on the left with the simplified version on the right.

Mathematics
1 answer:
Vitek1552 [10]1 year ago
3 0

Given the following question:

First expression:

\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}

Second expression:

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Remember to follow PEMDAS, and left -> right rule.

First, solve the Parenthesis:

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Solve the exponent.

2^3 = 2 x 2 x 2 = 4 x 2 = 8

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_______________________________________________________________

(5^2) x (12)

5^2 = 5 x 5 = 25

25 x 12

_______________________________________________________________

Multiply

25 x 12 = 300

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300 is your answer

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<em>~Rise Above the Ordinary</em>

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