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2 years ago

Solve for w: w+6tw=11-w

1 answer:

7 0

w+6tw=11-w

Let's solve for w.

w+6tw=11−w


Step 1: Add w to both sides.
6tw+w+w=−w+11+w
6tw+2w=11
Step 2: Factor out variable w.

w(6t+2)=11
Step 3: Divide both sides by 6t+2.

w(6t+2)/6t+2=11/6t+2

Answer: 11/6t+2

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Which number is not a rational number?

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2 years ago

EASY MATH QUESTION PLEASE HELP

Juli2301 [7.4K]

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3 years ago

Graph y= x−2. PLZZ HELP

nataly862011 [7]

Explanation: To graph the equation y = x - 2, the idea is simple.

We pick three values for x, plug them into the

equation, and find the corresponding values for y.

In order to do this in an organized way, we set up a chart.

Down the left side we make a column for our x's, down the right side we make a column for our y's, and in the middle we make a column for the side of the equation that contains the x, in this case, x - 2.

So reading the chart from left to right, we have our x or what we plug into the equation, then we have the x - 2 or what happens to the x when we plug it into the equation, and finally we have our y or what we end up with after plugging x into the equation.

So our first step in filling out the chart is choosing

the x's that we want to plug into the equation.

When graphing lines, I always choose three x's,

a positive number, zero, and a negative number.

The easiest numbers to pick are usually 1, 0, and -1.

So for 1, we plug a 1 into the equation for x

and we have y = (1) - 2 or -1

For 0 we plug a 0 into the equation for x

and we have y = (0) - 2 or -2.

For -1 we plug a -1 into the equation for x

and we have y = (-1) - 2 or -3.

So our points are (1, -1), (0, -2), and (-1, -3).

I looked at the x and y column to find those points.

Since our domain is all real numbers, we can connect these points based on the pattern that they are forming on the graph which is a line.

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3 years ago

Read 2 more answers

Direction: Determine whether the given point is a solution to the given system of linear inequalities.

Ann [662]

Answer:

The given point is a solution to the given system of inequalities.

Step-by-step explanation:

Again, we can substitute the coordinates of the given point into the system of inequalities. We know that the x-coordinate and y-coordinate of $(3,2)$ are $x=3$ and $y=2$ , respectively.

Plugging these values into the first inequality, $y\leq x+3$ , gives us $2\leq 3+3$ , which simplifies to $2\leq 6$ . This is a true statement, so the given point satisfies the first inequality. We still need to check if it satisfies the second inequality though, because if it doesn't, it won't be a solution to the system.

Plugging the coordinates into the second inequality, $y\geq -x+3$ , gives us $2\geq -3+3$ , which simplifies to $2\geq 0$ . This is also a true statement, so the given point satisfies the second inequality as well. Therefore, $\bold(\bold3\bold,\bold2\bold)$ is a solution to the given system of inequalities since it satisfies all of the inequalities in the system. Hope this helps!