If one game needs two* players, and there are 5 games,
you multiply two by five to get ten players total.
To answer this question, we need to know what like terms are. Like terms are terms whose variables and exponents are the same. The coefficients can be different, though. In this case, the like terms are -a²b and 5a²b (because of the definition above.
9000000+60000+2000+10+6
Hope this is what you were looking for!!
Answer:
Step-by-step explanation:
<u>Perimeter of garden A is
</u>
- P = 2(w + l) = 2( 2x - 3 + 5(2x - 3)) = 24x - 36
<u>Perimeter of garden B is
</u>
-
5x + 5 + 4x + 2 + 8x - 8 = 17x - 1
<u>Sum of perimeters:</u>
- 24x - 36 + 17x - 1 = 41x - 37
The statement 2 is FALSE as number we got is different from the one in the statement
Answer:
- height: 9 chi 6 cun
- width: 2 chi 8 cun
Step-by-step explanation:
The factor-of-ten relationship between the different units means we can combine the numbers in decimal fashion. If 1 unit is 1 zhang, then 1 chi is 0.1 zhang and 1 cun is 0.01 zhang. Hence 6 chi 8 cun is 0.68 zhang.
Let x and y represent the width and height, respectively. In terms of zhang, we have ...
y - x = 0.68
x^2 +y^2 = 1^2
Substituting y = 0.68 +x into the second equation gives ...
x^2 + (x +0.68)^2 = 1
2x^2 +1.36x - 0.5376 = 0 . . . . . eliminate parentheses, subtract 1
Using the quadratic formula, we have ...
x = (-1.36 ±√(1.36^2 -4(2)(-0.5376)))/(2·2) = (-1.36 ±√6.1504)/4
x = 0.28 . . . . . the negative root is of no interest
y = 0.28 +0.68 = 0.96
In units of chi and cun, the dimensions are ...
height: 9 chi 6 cun
width: 2 chi 8 cun
