Answer:
The prove is as given below
Step-by-step explanation:
Suppose there are only finitely many primes of the form 4k + 3, say {p1, . . . , pk}. Let P denote their product.
Suppose k is even. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
ThenP + 2 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 2 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠2. This is a contradiction.
Suppose k is odd. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
Then P + 4 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 4 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠4. This is a contradiction.
So this indicates that there are infinite prime numbers of the form 4k+3.
Answer:
10%
Step-by-step explanation:
Sean first thought that his hand was 20 cm so:
20cm
When he measures with a ruler, he gets 18 cm so:
18cm
The equation is really simple, and you basically do:
20/20 - 18/20 = 2/20 = 1/10 = 10%
The equation is:
1- x/y
x equals the new number
y equals the original number
Answer:
C
Step-by-step explanation:
You know that if its < or >, the line is - - - -, not a fully dark line.
So it would be either A or C
Plot in some numbers for x
Less than would be to the left.
So it wouldn't be A, leaving us with C
Start by distributing -5x into x then into -3y. So -5x times x equals -5x^2( -5x squared), then -5 times -3y, equals 15xy so your answer is -5x^2 + 15xy.
