Hey there!!
In order to solve this question, we take the area as 196 as these are the total number of plants to cover a specific place.
The formation must be in a square formation
area of a square = ( s ) ²
s = side
or the number of plants in a row
s² = 196
s = √196
s = 14
There are 14 plants in each row
Hope my answer helps!
Please use the solution below:
Let P = perimeter, A = area
As provided above, a = xy and
We know that the formula to solve for the perimeter of a rectangle is P = 2x + 2y. Using the given 112m, we can solve the perimeter using the formula:
112 = 2x + 2y
56 = x + y
x = 56-y or y = 56-x
Let's solve the perimeter in terms of y using the formula below:
A = (56-y)(y)
Find the derivative of A = 56-y^2 to get the value of y.
dA/dy = 56-2y = 0
y = 56/2
y = 28
To find X, substitute the value of y in the equation x = 56 - y.
x = 56 - 28
Therefore, x = 28.
We can conclude that the figure is not a rectangle but a square.
1q+2=-6q+3+8q+4
1q+2=2q+7
<span>-2q -2q
</span>-q+2=7
<span> -2 -2
</span>-q=<span>5
-1 -1
q=-5
</span>
1. -3x and -6x
2. 21 and -13
3. 21 and -13
4. -10b and 6b, 15 and -5
5. -20 and 30, 4c and -2c
