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kifflom [539]
4 years ago
14

Amy, since you know something about algebra, you can probably help me out with this. what is the value of x in the equation x2 +

3x = 22?
Mathematics
1 answer:
umka21 [38]4 years ago
6 0
<span>I am not Amy but I would love to help you.


</span>x^2 + 3x = 22

x^2+ 3x - 22 = 0

\Bigg( {Formula: \ x = \frac{-b \pm \sqrt{b^2 -4ac} }{2a} \Bigg) 

a = 1, \ b = 3, \ c = -22

x = \frac{-3 \pm \sqrt{3^2 -4(1)(-22)} }{2(1)}

x = 3.42 \ or -6.42
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Consider the graph of the expotential function y= 3(2)^x
victus00 [196]

Answer:

<h2>y-intercept = 3</h2><h2>x-intercept - not exist</h2><h2>the graph is increasing</h2>

Step-by-step explanation:

The exponential function:

f(x)=b(a)^x

has y-intercept for x = 0

hasn't x-intercept

if a > 1, then is increasing

if 0 < a < 1, then is decreasing

We have

y=3(2)^x

a = 2 >1 - increasing

for x = 0:

y=3(2)^0=3(1)=3

8 0
4 years ago
Please help, I added a photo to show the question. I’m so confused and I need help, so if you could show work I’d really appreci
Mashutka [201]




Angle A = 30 and its complement would be 60. This is because both angles must equal 90 degrees, and 30 + 60 = 90. Also in the directions it states Angle A must be half of its complement. 30 is half of 60. Sorry I don’t have any work, I just did it in my head!

Any questions? Hope this helps!






7 0
3 years ago
Read 2 more answers
Which of the following is most likely the next step in the series?
zysi [14]

Answer:

it's D

Step-by-step explanation:

3 0
3 years ago
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I need help i will mark brainliest​
GalinKa [24]

Answer:

-2?

Step-by-step explanation:

Multiply -1 by -4 to get 4

subtract 20 from 12 to get -8

\frac{-8}{4} simplify to get -2

6 0
3 years ago
Find the equation of the tangent line to the curve <br> 2exy=x+y at (0,2).
DiKsa [7]

Answer:

The equation of the tangent line to the curve

3 x - y = 2

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function  = f(x,y) = 2e^{xy} -x-y=0   ...(i)

Differentiating equation (i) with respective to 'x' , we get

2 e^{xy} \frac{d}{d x} (x y) -1 -\frac{dy}{dx} =0

apply  formula

\frac{d}{dx} (UV) = UV^{l} +V U^{l}

<u><em>step(ii):-</em></u>

⇒   2 e^{xy} (x(\frac{d}{d x} ( y))+y(1)) -1 -\frac{dy}{dx} =0

⇒ 2 e^{xy} (x(\frac{d}{d x} ( y))+ 2e^{xy} y(1)) -1 -\frac{dy}{dx} =0

Taking common d y/d x

(2 e^{xy} (x) -1)\frac{dy}{dx} =1- 2e^{x y} y(1))

\frac{dy}{dx} =\frac{1- 2e^{x y} y(1))}{(2 e^{xy} (x) -1)}

put At (0,2)

\frac{dy}{dx} =\frac{1- 2e^{0} 2(1))}{(2 e^{0} (0) -1)}=\frac{1-4}{-1} =3

slope of the curve m = 3

<u><em>Step(iii)</em></u>:-

The equation of the tangent line to the curve

y-y_{1} =m(x-x_{1} )

y - 2 = 3 ( x - 0 )

3 x - y = 2

<u><em>Final answer:-</em></u>

The equation of the tangent line to the curve

3 x - y = 2

8 0
3 years ago
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