Let the slower runners speed be X kilometers per hour.
Then the faster runners speed would be X+2 kilometers per hour.
The formula for distance is Speed times time.
The distance is given as 30 kilometers and time is given as 3 hours.
Since there are two runners you need to add the both of them together.
The equation becomes 30 = 3x + 3(x+2)
Now solve for x:
30 = 3x + 3(x+2)
Simplify:
30 = 3x + 3x +6
30 = 6x + 6
Subtract 6 from each side:
24 = 6x
Divide both sides by 6:
x = 24/6
x = 4
The slower runner ran at 4 kilometers per hour.
The faster runner ran at 4+2 = 6 kilometers per hour.
Answer:
D. 8
Step-by-step explanation:
2p=16
divide both sides by 2 to get p alone
p=8
In a mechanical system, it is a law that energy should be conserved. In this case, what is the initial energy should be equal to the total energy after the motion happened. We do as follows:
PE(at rest) = KE(during motion) + PE(after motion)
51450 J = KE(during motion) + 32781 J
KE(during motion) = 18669 J
Answer:
4
Step-by-step explanation:
lim (x^2 - 4) / (x - 2)
x --> 2
When we plug x =2, we get
(2^2 - 4) / (2 - 2)
= (4 - 4)/(2 - 2)
= 0 /0
Which is undefined.
Now we have to use L'hospital rule. Which says we need to differentiate the numerator and the denominator and apply the limit.
When we differentiate x^2 -4, we get 2x
When we differentiate x -2, we get 1
lim 2x/1
x --> 2
Now apply, the limit x = 2
2(2)/1
= 4/1
= 4
Therefore, limit of this function is 4, when x tends to 2.
Hope you will understand the concept.
Thank you.
Answer is 1
Step-by-step explanation:
