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Norma-Jean [14]
3 years ago
7

a vector points 12.0 units along the x-axis and 9.00 units along the y-axis. find the magnitude of the vector

Physics
1 answer:
Umnica [9.8K]3 years ago
5 0

Explanation:

R = \sqrt{(12.0)^{2} + (9.00)^{2}} = 15 UNIDADES

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Which are characteristics of concave mirrors? Check all that apply.
aalyn [17]

Answer:

the answers are 1 2 and 5!

5 0
4 years ago
Which wave lies adjacent to the low frequency portion of the visible spectrum
fgiga [73]

Answer: b. infrared

Explanation:

The visible light with the smaller frequency is associated with the color red.

While the blue is the one with the larger frequency.

Now, as the name says, infrared waves are the ones with a frequency just below the one of the red visible light.

Where the frequency of the red light is something around (4.3*10^14 Hz)

and the frequency of the infrared waves is in the range between (10^12 Hz and 10^14 Hz)

Then the correct option is b, infrared.

8 0
3 years ago
Why do baseball pitchers throw the ball at an angle that is slightly above the horizontal if they want the ball to reach at appr
lesantik [10]

Answer:

The angle above the horizontal at which the pitcher throws the ball determines the distance the ball travels before returning to the height at which it was thrown

Explanation:

The baseball is thrown as a projectile and the range, 'R', of the baseball which is the distance the baseball travels before the height above the ground returns to the initial height  is given given as follows;

R = \dfrac{u^2 \cdot sin(2\cdot \theta )}{g}

Where;

R = The range of the baseball = The horizontal distance away from the pitcher the ball reaches

u = The initial velocity with which the baseball was thrown

θ = The angle above horizontal a baseball pitcher throws the ball

g = The acceleration due to gravity ≈ 9.81 m/s²

From the the equation, when θ = 0, sin(θ) = sin(0) = 0 and the ball does not cover any horizontal distance before going lower than the height at which it was thrown, therefore, for the ball to travel further, the angle of launch, θ has to be larger than 0.

4 0
3 years ago
A receiver catches a football on the 50.0 yard line and is tackled 5.42 seconds later on the 12 yard line. What
tester [92]

Answer:

7.01yard/sec

Explanation:

Given parameters:

Initial position  = 50yard

Final position = 12yard

Time  = 5.42s

Unknown:

Average speed of runner  = ?

Solution:

To solve this problem;

        Speed  = \frac{distance}{time}  

Distance covered  = Initial position  - final position  = 50 - 12  = 38yards

So;

       Speed  = \frac{38}{5.42}   = 7.01yard/sec

5 0
3 years ago
An object moves in a circular path at a constant speed. what is the direction of the net force acting on the object?
mr Goodwill [35]
In a circular motion im pretty sure
6 0
4 years ago
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