Answer:
Vf = 210 [m/s]
Av = 105 [m/s]
y = 2205 [m]
Explanation:
To solve this problem we must use the following formula of kinematics.

where:
Vf = final velocity [m/s]
Vo = initial velocity = 0 (released from the rest)
g = gravity acceleration = 10 [m/s²]
t = time = 21 [s]
Vf = 0 + (10*21)
Vf = 210 [m/s]
Note: The positive sign for the gravity acceleration means that the object is falling in the same direction of the gravity acceleration (downwards)
The average speed is defined as the sum of the final speed plus the initial speed divided by two. (the initial velocity is zero)
Av = (210 + 0)/2
Av = 105 [m/s]
To calculate the distance we must use the following equation of kinematics

44100 = 20*y
y = 2205 [m]
Answer:
No there is no displacement observed so no work done
The gravitational energy is going up subtracting the energy that was on the ground
Answer:
B.6.86 m
Explanation:
Given that
Compression in spring ,x= 9 cm
Spring constant ,K= 830 N/m
Mass of the rocket ,m= 50 g = 0.05 kg ( 1 kg = 1000 g)
Now by applying energy conservation


Now by putting the values ( we are taking g= 9.81 m/s²)

h= 6.853 m
Therefore the answer is B.
B.6.86 m