Question

A straight conductor carries a current of 755 A from east to west. It is 5.80 m above the ground. Part A Find the magnitude of the magnetic field due to the conductor at a point on the ground. B = nothing T Request Answer Part B Find the direction of the magnetic field at a point on the ground. Find the direction of the magnetic field at a point on the ground. to the north to the south to the east to the west

Answer 1

Answer:

a. 2.6*10^{-5}T

b. north to south

Explanation:

In this case you have to take into account the expression for the magnetic field generated by a current

$B=\frac{\mu_0I}{2\pi r}$

where mu0 is the magnetic permeability of vacuum, I is the current and r is the distance to the conductor in which you want to measure the field.

A) By replacing we have

$B=\frac{(4\pi *10^{-7}\frac{T}{mA})(755A)}{2\pi (5.80m)}=2.6*10^{-5}T$

B) The direction is obtained by using the right hand rule. In this case, the current is from west to east. Then the direction is from north to south

Hope this helps!!