Answer and Explanation:
Find enclosed the Lewis diagrams for ozone (O₃) resonance structures. The diagram shows the two main contributing structures (I and II) with their formal charges.
The formal charge (FC) is determined as follows:
FC= number of valence electrons in free atom - 1/2 (number of bonding electrons) - number of non bonding electrons
The O central atom has the formal charge +1:
FC= 6 - 1/2(6) - 2= +1
The O atom on the right in structure I and on the left in structure II has the formal charge -1:
FC= 6 - 1/2(2) - 6= 6 - 1 - 6 = -1
The O atom on the left in structure I and on the right in structure II has the formal charge 0:
FC= 6- 1/2(4) - 4= 6 - 2 - 4= 0
<u>Answer:</u> The standard EMF of the cell is 1.11 V
<u>Explanation:</u>
For the given chemical equation:
The half reaction follows:
<u>Oxidation half reaction:</u> ( × 3)
<u>Reduction half reaction:</u>
To calculate the of the reaction, we use the equation:
Substance getting oxidized always act as anode and the one getting reduced always act as cathode.
Calculating the using above equation, we get:
Hence, the standard EMF of the cell is 1.11 V