Question

500.0 mL of a 0.455 M solution of LiBr is diluted to 700.0 mL. What is the new concentration of the solution?

Answer 1

$\\ \tt\rightarrowtail M1V1=M2V2$

$\\ \tt\rightarrowtail 0.455(0.5)=0.7M2$

$\\ \tt\rightarrowtail 0.2275=0.7M2$

$\\ \tt\rightarrowtail M2=0.2275/0.7$

$\\ \tt\rightarrowtail M2=0.325M$