Pure water has a freezing point of 0 degrees centigrade but seawater has a lower freezing point because of the salt (NaCl)
So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+
Answer: 0.405g
Explanation:
Molar Mass of Be = 9g/mol
Number of mole of Be = 0.045mol
Mass conc. Of Be = 0.045 x 9 = 0.405g
L
mol/dm³ is measure for molarity
Answer:
A and D are the answers
Explanation:
the other two don't make sense
