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Masteriza [31]
2 years ago
10

Cl- and Ca2+

Chemistry
1 answer:
evablogger [386]2 years ago
7 0

  • they are both in thier octet state

differences

  • Cl loses 1 electrons to become stable
  • Ca2 gains one electrons to become stable
You might be interested in
4. By what quantity must the heat capacity be divided to obtain the specific heat of that material? (I poin
charle [14.2K]

Answer:

its mass

its temperature

Explanation:

The heat capacity of a body is the amount of heat needed to raise that temperature of a body by 1k or 1°C.

It is expresses as:

              H = m c Ф

where m is the mass of the body

           c is the specific heat of the body

           Ф is the temperature change of the body

Specific heat capacity is that heat content needed to raise the temperature of a unit mass of a substance by 1k or 1°C

Heat capacity is also known as heat content;

 To solve the problem:

 since H = m c Ф

  we make the unknown c the subject of the expression;

                c = \frac{H}{m (t_{2} - t_{1} )} = H / mФ

So to obtain the specific heat capacity, divided the heat capacity by mass and its temperature change.

8 0
3 years ago
Based on the kinetic molecular theory (KMT), which statement is true?
nataly862011 [7]

Statement 1 is false because heat is the movement of molecules.

Statement 2 is true because matter is composed of elementary particles which are VERY small.

Statement 3 is false because the kinetic energy of a particle determines its heat and it is impossible for a particle to be completely motionless.

Statement 4 is false because neutrons do not have a charge and make up a large portion of all matter.  

5 0
2 years ago
The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at
seraphim [82]

Answer:

the solubility of CaCO3 is 0.015g/l 25 °C

is favored at equilibrium

Explanation:

The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at equilibrium?

solubility is the property of a solute to dissolve in a solvent(liquid, gas ) to form a solution(soution can be saturated ,unsaturated, or supersaturated)

CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq)

in partial dissociation , we can say

2.25x 10^-8=Ca^{2+} +CO^{2-}_{3} }

let Ca^2+=CO3^-2=S

2.25x10^-8=S*S

S^2=2.25x10^-8

S=0.00015mol/L

Converting that to g/l

the relative molecular mass of CaCO3=100g/mol

0.00015*100g/mol

0.015g/l

the solubility of CaCO3 is 0.015g/l @room temperature

is favored   at equilibrium

5 0
3 years ago
two atoms respectively have Z=12, A=26 and Z=14, A=26. Can these two atoms be classified as isotopes of the same element?
aleksley [76]
No because they have the same number of protons not neutrons. fine, their mass nos are equal but isotopy is due to different number of neutrons.
6 0
2 years ago
Solid ammonium chloride, NH4Cl, is formed by the reaction of gaseous ammonia, NH3, and hydrogen chloride, HCl. NH3(g)+HCl(g)⟶NH4
Mashutka [201]

9.41 atm is the pressure in atmospheres of the gas remaining in the flask

<h3>What is the pressure in atmospheres?</h3>

The equation NH3(g) + HCl(g) ==> NH4Cl(s) is balanced.

Divide the moles of each reactant by its coefficient in the balanced equation, and the limiting reagent is identified as the one whose value is less. With the issue we now have...

6.44 g NH3 times 1 mol NH3/17 g equals 0.3688 moles of NH3 ( 1 = 0.3688)

HCl: 6.44 g of HCl times one mole of HCl every 36.5 g equals 0.1764 moles ( 1 = 0.1764). CONTROLLING REAGENT

NH4Cl will this reaction produce in grams

0.1764 moles of HCl multiplied by one mole of NH4Cl per mole of HCl results in 9.44 g of NH4Cl (3 sig. figs.)

the gas pressure, measured in atmospheres, that is still in the flask

NH3(g) plus HCl(g) results in NH4Cl (s)

0.3688......0.1764............0..........

Initial

-0.1764....-0.1764........+0.1764...Change

Equilibrium: 0.1924.......0...............+0.1924

There are 0.1924 moles of NH3 and no other gases in the flask. This is at a temperature of 25 °C (+273 = 298 °K) in a volume of 0.5 L. After that, we may determine the pressure by using the ideal gas law (P).

PV = nRT

P = nRT/V = 0.1924 mol, 0.0821 latm/mol, and 298 Kmol / 0.5 L

P = 9.41 atm

9.41 atm is the pressure in atmospheres of the gas remaining in the flask

To learn more about balanced equation refer to:

brainly.com/question/11904811

#SPJ1

7 0
1 year ago
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