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3 years ago

Can somebody help me?

Mathematics

1 answer:

lubasha [3.4K]3 years ago

8 0

Answer:

13, 13√3, 26

Step-by-step explanation:

30 60 90 right triangle

Ratio of short leg : long leg : hypo = a : a√3 : 2a

Given short leg = 13, so long leg = 13√3 and hypo = 13 * 2 = 26

Answer:

13, 13√3, 26

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The infinite geometric series S=1+( 2/3 )+( 2/3 )^ 2 +( 2/3 )^ 3 .... equal to:

weqwewe [10]

SOLUTION

The question simply means that we should find the sum to infinity of the geometric series.

The formula of sum to infinity of a geometric serie is given by

$S_{\infty}=\frac{a}{1-r}$

Where

$\begin{gathered} S_{\infty}\text{ is the sum to infinity} \\ \\ a\text{ is the first term = 1} \\ \\ r\text{ is the common ratio = }\frac{2}{3} \end{gathered}$

So, this becomes

$\begin{gathered} S_{\infty}=\frac{a}{1-r} \\ \\ S_{\infty}=\frac{1}{1-\frac{2}{3}} \\ \\ S_{\infty}=\frac{1}{\frac{3-2}{3}} \\ \\ S_{\infty}=\frac{1}{\frac{1}{3}} \\ \\ S_{\infty}=3 \end{gathered}$

Therefore, option b is the correct answer

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1 year ago

Find three points that belong to the graph and use them to sketch the graph of the equation: y = −3 −x

dalvyx [7]

Answer:

To find a point that belongs to the graph, you have to assume the value of one variable and compute the other one. For example, if x = 0, then y = -3 -0 = -3. Similarly:

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3 years ago

If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____

Sauron [17]

<h2>Answer:</h2>

$2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}$

<h2>Step-by-step explanation:</h2>

In this problem we have two vectors:

$\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)$

So we need to find two things:

$2\vec{v}-6\vec{u}$

and:

$||2\vec{v}-6\vec{u}||$

FIRST:

In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:

$2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}$

SECOND:

If we name:

$\vec{w}=2\vec{v}-6\vec{u}$

Then, $||2\vec{v}-6\vec{u}||$ is the magnitude of the vector $\vec{w}$ . Therefore:

$||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}$

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Hunter-Best [27]

Answer:

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Step-by-step explanation:

121 /132

Divide the top and bottom by 11

121/11 =11

132/11 =12

121/132 =11/12

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3 years ago