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3 years ago

9 2 199843x199813996 1998-1998

Mathematics

1 answer:

Mashutka [201]3 years ago

5 0

Answer:

what exactly did u want me to work out?

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URGENT PLS RESPOND!!!

Elan Coil [88]

Answer:

$\huge\boxed{d=\sqrt{17}}$

Step-by-step explanation:

Simply use the fact that the change in x squared + the change in y squared = the distance squared. (The Pythagorean Theorem)

1^2 + 4^2 = d^2

1 + 16 = d^2

17 = d^2

d = √17

Hope it helps :)

6 0

2 years ago

The nth term of a sequence is n^2 -n-2 .find the sum of the first and third terms

Troyanec [42]

Answer:

Step-by-step explanation:

substitute n=1 and n=3 in the given equation

1 st term is (1)^2-1-2 = 1 -1 -2 = -2

3rd term is (3)^2-3-2 = 9-3-2=4

sum of 1st and 3rd term is -2 + 4 = 2

8 0

3 years ago

To control an infection, a doctor recommends that a patient who weighs 92 pounds be given 320 milligrams of antibiotic. If the a

stich3 [128]

Answer:

480 milligrams.

Step-by-step explanation:

Divide 320 by 92, you get 3.47826087, multiply that by 138 to get your answer (480).

7 0

3 years ago

Read 2 more answers

If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$

3 0

3 years ago

Rekitha arekitha kandaralu

lions [1.4K]

Answer:

khing chong

Step-by-step explanation:

8 0

2 years ago