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Anit [1.1K]
3 years ago
12

9 2 199843x199813996 1998-1998

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

what exactly did u want me to work out?

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The cd club offers a discount when you purchase 3 or more cd’s. If the price of each cd is reduced by $1.50 and the cost of 3 cd
Natali5045456 [20]
11.99 per cd's your welcome
4 0
3 years ago
1/7=3/4x+1<br><br> Please help
zloy xaker [14]
Here, 1/7 = 3/4x + 1
3/4x = 1/7 - 1
3/4x = -6/7
x = -6/7 * 4/3
x = -2/7 * 4
x = -8/7

In short, Your Answer would be -8/7

Hope this helps!
3 0
3 years ago
Read 2 more answers
Pentagon RSTUV is circumscribed about a circle. What is the value of x if RS = 10, ST = 13, TU = 11, UV = 12, and VR = 12?
Kobotan [32]

Answer:

Step-by-step explanation:

The value of x is 7 ⇒ 1st answer

Step-by-step explanation:

* Lets revise a fact in the circle

- The two tangents drawn from a point out side the circle are equal

∵ RSTUV is circumscribed about a circle

∴ Each side of the pentagon is a tangent to the circle

- Look to the attached figure to know how we will solve the problem

- Each tangent divided into two parts

# RS = x + y

∵ RS = 8

∴ x + y = 8 ⇒ (1)

# RV = x + n

∵ RV = 12

∴ x + n = 12 ⇒ (2)

- Subtract (2) from (1)

∴ y - n = -4 ⇒ (3)

# ST = y + z

∵ ST = 12

∴ y + z = 12 ⇒ (4)

# TU = z + m

∵ TU = 15

∴ z + m = 15 ⇒ (5)

- Subtract (5) from (4)

∴ y - m = -3 ⇒ (6)

# UV = m + n

∵ UV = 9

∴ m + n = 9 ⇒ (7)

- Add (6) and (7)

∴ y + n = 6 ⇒ (8)

- Lets solve equation (3) and equation (8) to find y

∵ y - n = -4 ⇒ (3)

∵ y + n = 6 ⇒ (8)

- Add (3) and (8)

∴ 2y = 2 ⇒ divide two sises by 2

∴ y = 1

- Lets substitute the value of y in equation (1)

∵ x + y = 8 ⇒ (1)

∵ y = 1

∴ x + 1 = 8 ⇒ subtract (1) from both sides

∴ x = 7

* The value of x is 7

plz mark me as brainlyist thxx

7 0
2 years ago
Read 2 more answers
What is the center and radius of -10x = -121 - y2 - x2 -22y
OlgaM077 [116]

We need to find the center and the radius of

-10x\: =\: -121\: -\: y^2\: -\: x^2\: -22y

The general circle equation is the following

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center and

r is the radius

1. rearrange the equation

(x^2-10x)+(y^2+22y+121)=0

2. Add 25 on both sides

(x^2-10x+25)+(y^2+22y+121)=25

3. Factor

(x-5)^2+(y+11)^2=5^2

Now we have an equation that is very similar to the circle equation, so let's compare them

Center -> (h,k) = (5,-11)

radius -> r = 5

8 0
1 year ago
Solve for x in the equation p(m+qx)=rx+n
katrin [286]

p(m+qx)=rx+n\\\\\implies pm+pqx = rx+n\\\\\implies pqx-rx = n-pm\\\\\implies x(pq -r) = n-pm\\\\\implies x = \dfrac{n-pm}{pq-r}

6 0
2 years ago
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