Answer:
absolute vlaue inequality: |x-3| > 9; solved: x<-6 and x>12
Step-by-step explanation:
I’m going to start this off by saying I learned all this right now by just searching up how to solve an absolute inequality equation and watching one video, so this might not be an accurate explanation. (I’m pretty sure the answer’s right though)
So an absolute value inequality must be written like this:
| x - a | *inequality* b
a is going to be the number that the inequality is centered around, in this case, 3. b will be how far you can deviate from that number, which in this case is 9.
Now, you will have this:
|x - 3| *inequality* 9
Now, to find the inequality, you need to understand the wording. If it says “more than” as it does here, then you would have the greater-than symbol (>). If you have “less than” then you’d have the less-than symbol (<). If the problem says “at least b away” then it would be greater-than-or-equal to (≥), and likewise, if it says “at most b away” then it would be less-than-or-equal-to (≤).
So now we're at:
|x - 3| > 9
To solve the equation, you just need to subtract 9(b) from 3(a) and add 9(a) to 3(b) to get -6 and 12. Since x must be more than 9 units away, you would get:
x<-6 and x>12
Hope this is helpful!
Add the following polynomials:
All polynomials are already ordered according to their degree (exponent), and therefore you can just add straight down in columns.
For x3: 2 + 1 - 3 = 0
For x2: -4 + 6 + 2 = 4
For x: 6 - 8 -4 = -6
Constants: -3 + 12 - 7 = 2
The answer is:
4x^2 - 6x + 2
C=5.20/8=$0.65
1 $0.65
10 $6.50
18 $11.70
24 $35.10
Hope this helps. Mark as branliest tq
Answer:
![\sqrt[3]{7x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7x%7D)
Step-by-step explanation:
Given
Required
The radical statement
Cube root is represented as:
![\sqrt[3]{}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D)
Considering , the expression is:
Divide 12 into 96 probably
