1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mars2501 [29]
3 years ago
7

Write each fraction as a percent. Use a model if needed. V-2

Mathematics
2 answers:
alexandr402 [8]3 years ago
8 0
7/10 = 70%
21/25 = 84%
3/5 = 60%
18/25 = 72%
igomit [66]3 years ago
5 0
7/10 is 70%
21/25 is 84%
3/5 is 60%
18/25 is 72%
You might be interested in
What is 600,000,000 in scientific notation ?
Alenkinab [10]

Answer:

6 x 108 in scientific notation

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve the systems of equation by graphing (Picture provided)
padilas [110]

Answer:

The option d

Step-by-step explanation:

find the intersection with x and y

https://tex.z-dn.net/?f=x%3D0%0A

https://tex.z-dn.net/?f=0%2By%3D-9%20%5Clongrightarrow%20y%3D-9%0A

and https://tex.z-dn.net/?f=y%3D0%0A

https://tex.z-dn.net/?f=x%2B0%3D-9

we get the coordinates

https://tex.z-dn.net/?f=(0%2C-9)%2C%20(-9%2C0)

and the same process for another equation

https://tex.z-dn.net/?f=4*(0)%2By%3D-19%20%5Clongrightarrow%20y%3D-19%5C%5C%0A4*x%2B0%3D-19%20%5Clongrightarrow%20x%3D%5Cfrac%7B-19%7D%7B4%7D%20%5C%5C%5C%5C%0A(0%2C-19)%2C%20(%5Cfrac%7B-19%7D%7B4%7D%2C0)%20

and these coordinates are those expressed in the d graph

3 0
3 years ago
Population Growth A lake is stocked with 500 fish, and their population increases according to the logistic curve where t is mea
Alexus [3.1K]

Answer:

a) Figure attached

b) For this case we just need to see what is the value of the function when x tnd to infinity. As we can see in our original function if x goes to infinity out function tend to 1000 and thats our limiting size.

c) p'(t) =\frac{19000 e^{-\frac{t}{5}}}{5 (1+19e^{-\frac{t}{5}})^2}

And if we find the derivate when t=1 we got this:

p'(t=1) =\frac{38000 e^{-\frac{1}{5}}}{(1+19e^{-\frac{1}{5}})^2}=113.506 \approx 114

And if we replace t=10 we got:

p'(t=10) =\frac{38000 e^{-\frac{10}{5}}}{(1+19e^{-\frac{10}{5}})^2}=403.204 \approx 404

d) 0 = \frac{7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)}{(1+19e^{-\frac{t}{5}})^3}

And then:

0 = 7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)

0 =19e^{-\frac{t}{5}} -1

ln(\frac{1}{19}) = -\frac{t}{5}

t = -5 ln (\frac{1}{19}) =14.722

Step-by-step explanation:

Assuming this complete problem: "A lake is stocked with 500 fish, and the population increases according to the logistic curve p(t) = 10000 / 1 + 19e^-t/5 where t is measured in months. (a) Use a graphing utility to graph the function. (b) What is the limiting size of the fish population? (c) At what rates is the fish population changing at the end of 1 month and at the end of 10 months? (d) After how many months is the population increasing most rapidly?"

Solution to the problem

We have the following function

P(t)=\frac{10000}{1 +19e^{-\frac{t}{5}}}

(a) Use a graphing utility to graph the function.

If we use desmos we got the figure attached.

(b) What is the limiting size of the fish population?

For this case we just need to see what is the value of the function when x tnd to infinity. As we can see in our original function if x goes to infinity out function tend to 1000 and thats our limiting size.

(c) At what rates is the fish population changing at the end of 1 month and at the end of 10 months?

For this case we need to calculate the derivate of the function. And we need to use the derivate of a quotient and we got this:

p'(t) = \frac{0 - 10000 *(-\frac{19}{5}) e^{-\frac{t}{5}}}{(1+e^{-\frac{t}{5}})^2}

And if we simplify we got this:

p'(t) =\frac{19000 e^{-\frac{t}{5}}}{5 (1+19e^{-\frac{t}{5}})^2}

And if we simplify we got:

p'(t) =\frac{38000 e^{-\frac{t}{5}}}{(1+19e^{-\frac{t}{5}})^2}

And if we find the derivate when t=1 we got this:

p'(t=1) =\frac{38000 e^{-\frac{1}{5}}}{(1+19e^{-\frac{1}{5}})^2}=113.506 \approx 114

And if we replace t=10 we got:

p'(t=10) =\frac{38000 e^{-\frac{10}{5}}}{(1+19e^{-\frac{10}{5}})^2}=403.204 \approx 404

(d) After how many months is the population increasing most rapidly?

For this case we need to find the second derivate, set equal to 0 and then solve for t. The second derivate is given by:

p''(t) = \frac{7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)}{(1+19e^{-\frac{t}{5}})^3}

And if we set equal to 0 we got:

0 = \frac{7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)}{(1+19e^{-\frac{t}{5}})^3}

And then:

0 = 7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)

0 =19e^{-\frac{t}{5}} -1

ln(\frac{1}{19}) = -\frac{t}{5}

t = -5 ln (\frac{1}{19}) =14.722

7 0
3 years ago
What is 3 to the square root of 1089
Nana76 [90]
3 to square root of 1089 is

5.5590606e+15
8 0
2 years ago
EXPERT HELP I'LL GIVE BRAINLIEST:
ICE Princess25 [194]

Answer:

990, C

Step-by-step explanation:

The formula for the surface area of the bottom cushion is

A = 2wl + 2lh + 2hw (w is width, l is length, h is height)

w = 18, l = 21, h = 3

A = 2(18)(21) + 2(21)(3) + 2(3)(18)

A = 2(378) + 2(63) + 2(54)

A = 756 + 126 + 108

A = 990 (C)

5 0
3 years ago
Other questions:
  • Multiply 41 by the sum of 10 cubed and 5 squared.
    14·2 answers
  • 2)1694 what is the answer​
    15·1 answer
  • The answer choices are
    10·2 answers
  • Compare the maximum ,minimumand median of the dots plots???
    9·1 answer
  • This graph shows how the total distance Jack has walked depends on the number of trips he has made to school.
    14·2 answers
  • Use the information to answer the following questions. The angle measures of a triangle are shown. Angle A: (5x – 5) degrees Ang
    12·2 answers
  • Answer fast!!!
    11·1 answer
  • Https://linksharing.samsungcloud.com/dQg1FGA50fUL​
    6·1 answer
  • Can someone please help me with math.
    7·1 answer
  • 4 people can stay in a hotel for 5 days for $ 240. Find the bill for 5 people staying in
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!