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3 years ago

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Jetta is 2 years older than 1/3 merciless age and me is 4 years younger than 2 times Justin's age Define a variable and write an

expression to represent Justice age Define Justin's age in enemies a if Marcella is 63 years older

1 answer:

Tamiku [17]3 years ago

8 0

Answer:

2+24x+12

Step-by-step explanation:

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The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv

Rina8888 [55]

Answer:

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=14.42$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=6.95$ represent the population standard deviation

n=36 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

5 0

3 years ago

The 100-meter dash times in the girls track meet were normally distributed with a mean of 13 seconds and a standard deviation of

Svetllana [295]

Answer:

97.68 %

z(lower) = .0227

z(upper) = .999

Step-by-step explanation:

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3 years ago

Dion is performing a hypothesis test in which the population mean is 92 and the standard deviation is 2. His sample size is 7 wi

Elza [17]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Humans breathe about 15 breaths in a minute. The average

NeX [460]

Answer:

Humans breathe about 300 liters of air in 25 minutes

7 0

2 years ago

Consider a refrigerator that consumes 320 W of elec- tric power when it is running. If the refrigerator runs only one quarter of

irinina [24]

Answer: The refrigerator cost in this month is $4.5 approximately.

Step-by-step explanation:

Since we have given that

Amount of watt of electric power = 320 W

Number of days = 30

Unit cost of electricity = $0.13/Kwh

Hold factor = $\dfrac{1}{4}$

Number of hours in a month = 24

So, the refrigerator cost in this month would be

$0.13\times 0.32\times \dfrac{1}{4}\times 30\times 24\\\\=\$7.488$

Hence, the refrigerator cost in this month is $4.5 approximately.

3 0

3 years ago