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irina1246 [14]
2 years ago
13

Simplify the following expression log(x^2)-log(x)

Mathematics
1 answer:
Murrr4er [49]2 years ago
3 0

Answer:log a - log b = log (a/b) than use this formula will get

log x^2 -log x = log (x^2 /x) = log x

so answer is log x

Step-by-step explanation:

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HELP ASAP !! easy question and i’ll give brainliest
tia_tia [17]

Answer:

x=38.5

Step-by-step explanation:

\sqrt{23^{2}- 18^{2}}   =\sqrt{205}

cos(x)=\frac{18^{2} +23^{2} -205}{2(18)(23)}

x=38.5(correct to the nearest tenth)

4 0
3 years ago
Read 2 more answers
The tail of a kite is 1.5 feet plus twice the length of the kite. Together, the kite and tail are 15.5 ft long. Find the length
Ivan

Answer:

We know that the kite with the tail is 15 feet and 6 inches. While 6 inches is 0,50 foot, it's 15,5 feet. If the lenght of the kite is x, then:

15,5 = x + 1,5 + 2x

15,5 = 3x + 1,5     / - 1,5 (both sides)

14 = 3x             / : 3 (both sides)

x ≈ 4,66

The kite is approx .4,66 feet long. It means that the tail is about 15,5 - 4,66 = 10,84 feet long.

5 0
3 years ago
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Find the amount paid for the loan. $4800 at 9.9% for 4 years<br><br><br> note: its not 1900.8
Varvara68 [4.7K]
The answer is 7002 dollars
4 0
2 years ago
HELP PLEASE!!! Picture below!
Lady_Fox [76]

Answer:

7 (units)

Step-by-step explanation:

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8 0
2 years ago
Imagine a recessive mutation in rabbits that causes wiry fur (whereas the dominant, normal allele causes fluffy fur). If two het
arsen [322]

Answer: the required probability is  0.03516

Step-by-step explanation:

Given the data in the question;

let F represent dominant allele that causes fluffy fur and

f represent corresponding recessive allele that causes wiry fur

here are the possible genotypes and corresponding phenotypes;

FF = Fluffy fur

Ff = Fluffy fur

ff = Wiry fur

genotype of parents is Ff and Ff

and there cross will be; Ff x Ff

now Offspring will be;

                                   F                      f

F                                FF                    Ff

f                                 Ff                     ff

so the probability that the offspring will have fluffy fur = 3/4

and the probability that the offspring will have wiry fur = 1/4

The probability that the first 2 out of 4 offspring will have fluffy fur will be;

⇒ 3/4 × 3/4 × 1/4 × 1/4 =  0.03516

 Therefore, the required probability is  0.03516

6 0
2 years ago
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