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2 years ago

Simplify the following expression log(x^2)-log(x)

Mathematics

1 answer:

Murrr4er [49]2 years ago

3 0

Answer:log a - log b = log (a/b) than use this formula will get

log x^2 -log x = log (x^2 /x) = log x

so answer is log x

Step-by-step explanation:

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The area of a rectangular wall of a barn is 85 square feet. Its length is 12 feet longer than the width. Find the length and wid

MaRussiya [10]

Answer:

Length = 17 feet, Width = 5 feet

Step-by-step explanation:

Given:

The area of a rectangular wall of a barn is 85 square feet.

Its length is 12 feet longer than the width.

Question asked:

Find the length and width of the wall of the barn.

Solution:

Let width of a rectangular wall of a barn = $x$

<u>As length is 12 feet longer than the width.</u>

Length of a rectangular wall of a barn = $12+x$

As we know:

$Area\ of\ rectangle=length\times breadth$

$85=(12+x)x\\\\85=12x+x^{2} \\$

Subtracting both sides by 85

$x^{2} +12x-85=0\\x^{2} +17x-5x-85=0\\Taking\ common\\x+(x+17)-5x(x+17)=0\\(x+17)(x-5)=0\\x+17=0, x-5=0\\x=-17,x=5$

As width can never be in negative, hence width of a rectangular wall of a barn = $x$ = 5 feet

Length of a rectangular wall of a barn = $12+x=12+5=17\ feet$

Therefore, length and width of the wall of the barn is 17 feet and 5 feet respectively.

4 0

3 years ago

The linear scale factor of two similar solids is given. Then the surface area and volume of the smaller figure are also given. F

katen-ka-za [31]

Answer:

SA:48 V:144

Step-by-step explanation:

4 0

2 years ago

a fruit market sold 3,849 apples 3,498 oranges,and 3894 pears in one day.round each number to the nearest hundred.then order the

Ainat [17]

First is pears ,next is apple, and the last is oranges. 3,900, 3800, 3500. I hope that this helps.

5 0

3 years ago

A sample of gold has a mass of 579 g. The volume of the sample is 30 cm3. What is the density of the gold sample?

Ugo [173]

The density of the gold sample is 19.3g/cm³

Let the mass of the gold sample be represented by m

m = 579 g

Let the volume of the gold sample be represented by V

V = 30 cm³

Let the density of the gold sample be represented by ρ

The formula for the density is:

$Density = \frac{Mass}{Volume}$

$\rho = \frac{m}{V} \\\rho = \frac{579}{30} \\\rho = 19.3 g/cm^3$

The density of the gold sample is 19.3g/cm³

Learn more here: brainly.com/question/17780219

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2 years ago

Find the quotient 54÷3=

dangina [55]

60/3=20 57/3=19 54/3=18

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3 years ago

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