So, in order, you have to multiply first. 3x3=9, now you have to do 2+2=4. Since there is a "plus" in between "2+2" and "3x3" you have to add, 9+4=13.

7 0

4 years ago

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Write the factored form for a polynomial function of degree three that has zeros of 2, -3, and 0

ss7ja [257]

Answer:

x=-b/2a

Step-by-step explanation:

4 0

3 years ago

1( m² + 15m + 56) = (____) (m+8)<br>2 a² +5ab + 6b²=(a +2b (_____)<br><br>pastor po

Nutka1998 [239]

Step-by-step explanation:

${m}^{2} + 15m + 56 = ( \: \: \: \: \: )(m + 8) \\ solution \\ \: \: taking \: lhs \\ = {m}^{2} + 15m + 5 \\ = {m}^{2} + (7 + 8)m + 56 \\ \: \: \: \: = {m}^{2} + 8m + 7m + 56 \: \: \\ now \: taking \: common \: factor \\ m(m + 8) + 7(m + 8) \\ (m + 7)(m + 8) \\ now \\ {m}^{2} + 15m + 56 = (m + 7)(m + 8)$

${a}^{2} + 5ab + 6 {b}^{2} = ( a + 2b)( \: \: \: \: \: \: \: \: ) \\ solution \\ taking \: \: lhs \\ = {a}^{2} + 5ab + 6 {b}^{2} \\ = {a}^{2} + ( 3+ 2)ab + 6 {b}^{2} \\ = {a}^{2} + 3ab + 2ab + 6 {b}^{2} \\now \: taking \: common \: factor \\ a(a + 3b) + 2b(a + 3) \\ (a + 2b)(a + 3) \\ now \\ {a}^{2} + 5ab + 6 {b}^{2} = ( a + 2b)( a + 3) ans$

this may help you(:

7 0

3 years ago