Question

H(x+1)=x^2-4 evaluate function by substuting x+1

Answer 1

Answer:

h(x + 1) = (x+3)(x-1)

Step-by-step explanation:

Simply plug the value of x+1 into the equation for x.

h(x) = x^2 - 4

h(x + 1) = (x + 1)^2 - 4

h(x + 1) = x^2 + 2x + 1 - 4

h(x + 1) = x^2 + 2x - 3

h(x + 1) = (x+3)(x-1)

Cheers.

Answer 2

Answer:

h(t)= t² - 2t -3

Step-by-step explanation:

h(x+1)= x²-4 is the given function

We can write it x²-4 as:

• (x+2)(x-2)= (x+1+1)(x+1 - 3)

Substituting x+1  with  t. Then function is:

• h(t)= (t+1)(t-3)= t² - 2t -3

or

• h(t)= t² - 2t -3