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4 years ago

H(x+1)=x^2-4 evaluate function by substuting x+1

Mathematics

2 answers:

zalisa [80]4 years ago

8 0

Answer:

h(x + 1) = (x+3)(x-1)

Step-by-step explanation:

Simply plug the value of x+1 into the equation for x.

h(x) = x^2 - 4

h(x + 1) = (x + 1)^2 - 4

h(x + 1) = x^2 + 2x + 1 - 4

h(x + 1) = x^2 + 2x - 3

h(x + 1) = (x+3)(x-1)

Cheers.

Effectus [21]4 years ago

8 0

Answer:

h(t)= t² - 2t -3

Step-by-step explanation:

h(x+1)= x²-4 is the given function

We can write it x²-4 as:

(x+2)(x-2)= (x+1+1)(x+1 - 3)

Substituting x+1 with t. Then function is:

h(t)= (t+1)(t-3)= t² - 2t -3

h(t)= t² - 2t -3

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Read 2 more answers

The number of students in a class is 60. The number of boys is seven-fifths the number of girls. Find the number of boys in the

Fynjy0 [20]

Step-by-step explanation:

Let the number of girls = x

Therefore, no. of boys = $\frac{7}{5} \times x$

$\because \: no \: of \: boys + no \: of \: girls \: = 60 \\ \\ \therefore \: \frac{7}{5} x + x = 60 \\ \\ \therefore \: \frac{7x + 5x}{5} = 60 \\ \\ \therefore \: \frac{12x}{5} = 60 \\ \\ \therefore \: x = 60 \times \frac{5}{12} \\ \\ \therefore \: x = 5 \times 5 \\ \\ \therefore \: x = 25 \\ \\ \therefore \: \frac{7}{5} x = \frac{7}{5} \times 25 = 7 \times 5 = 35 \\$

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