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3 years ago

A pound of rice crackers costs $2.88.Matthew purchased 1/4 pound of crackers.How much did he pay for the crackers?

2 answers:

6 0

A pound of rice crackers ... $2.88
1/4 pound of crackers ... $x = ?

If you would like to know how much did Matthew pay for the crackers, you can calculate this using the following steps:

1 * x = 1/4 * 2.88
x = 1/4 * 2.88
x = $0.72

Result: Matthew paid $0.72 for 1/4 pound of crackers.

Allisa [31]3 years ago

4 0

He paid $0.72, because $2.88×(1÷4) = $0.72

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2 years ago

A die is rolled 20 times. given that three of the rolls came up 1, five came up 2, four came up 3, two came up 4, three came up

Serjik [45]

Solution:

Number of times a die is rolled = 20

1 - 3=A

2 - 5=B

3 - 4=C

4 - 2=D

5 - 3=E

6 - 3=F

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= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes

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8 0

3 years ago

A metal bar weighs 7 Kg. 93% of the bar is Silver. How many Kgs of silver is there in the bar?

Sindrei [870]

<h3>Solution:</h3>

<u>From the given data</u>

<u>93% of the bar is silver :</u>

$\small\bold{ → 93\% \: \: of \: \: 7kg}$

$\small \bold{→\frac{93}{100} \times 7 }$

$\small \bold{→ \frac{651}{100} }$

$\small \bold{→ 6.51 \: kg }$

<u>Therefore, 6.51 Kg of Silver is there in the bar.</u>

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2 years ago

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The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va

Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

$d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore$

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3 years ago