They affect the signs of p and q in different ways.
Firstly, if c is negative, it means that p and q have opposite signs.
If c is positive, then it means that p and q have the same signs. However, to determine whether they are both positive or both negative, we then have to look to b. If b is negative, both p and q would be negative. If b is positive, then both p and q are positive.
4.)y=-2x+7
6.)y=-4x+3
8.)y=3/4x+3/4
10.)y=2x+1
12.)y=16x-12
Geez that is real complicated sorry I’m not sure just go with your gut
Solve 32x-4=15x+3 and that should be the answer
Answer:the third option is correct
Step-by-step explanation:
The system of equations are
y = 2x^2 - 5x - 7 - - - - - - - - - - -1
y = 2x + 2 - - - - - - - - - - - - - 2
We would equate equation 1 and equation 2. It becomes
2x^2 - 5x - 7 = 2x + 2
2x^2 - 5x - 2x - 7 - 2 = 0
2x^2 - 7x - 9 = 0
We would find two numbers such that their sum or difference is -7x and their product is - 18x^2. The two numbers are 2x and - 9x. Therefore
2x^2 + 2x - 9x - 9 = 0
2x(x + 1) - 9(x + 1) = 0
2x - 9 = 0 or x + 1 = 0
2x = 9 or x = - 1
x = 9/2 = 4.5
Substituting x = 4.5 or x = -1 into equation 2, it becomes
y = 2 × 4.5 + 2 or y = 2 × - 1 + 2
y = 11 or y = 0
Therefore, the solutions are
(4.5, 11) (- 1, 0)