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vodka [1.7K]
3 years ago
12

V = e^3 when e = 7 please help me​

Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0

Answer:

343

Step-by-step explanation:

7^3=7×7×7=343

If e is equal to 7 just multiply 7 by 7 and then multiply that answer by 7 to find 7 to the power of 3.

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=1/3(3w - 12)= 1/6( 24-6w)
Taya2010 [7]
1w-4= 4-1w
+1w +1w
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2w-4=4
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—————
2w=8
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2. 2



w= 4
3 0
3 years ago
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What’s the least common multiple of x^2-2x-15 and x^2+2x-3?
Ghella [55]

Answer:

\large\boxed{LCM(x^2-2x-15,\ x^2+2x-3)=(x+3)(x-5)(x-1)}\\\boxed{=x^3-3x^2-13x+15}

Step-by-step explanation:

x^2-2x-15=x^2+3x-5x-15=x(x+3)-5(x+3)=(x+3)(x-5)\\\\\\x^2+2x-3=x^2+3x-1x-3=x(x+3)-1(x+3)=(x+3)(x-1)\\\\LCM(x^2-2x-15,\ x^2+2x-3)=(x+3)(x-5)(x-1)\\\\=(x^2-2x-15)(x-1)\qquad\text{use FOIL}\\\\=(x^2)(x)+(x^2)(-1)+(-2x)(x)+(-2x)(-1)+(-15)(x)+(-15)(-1)\\\\=x^3-x^2-2x^2+2x-15x+15\qquad\text{combine like terms}\\\\=x^3+(-x^2-2x^2)+(2x-15x)+15\\\\=x^3-3x^2-13x+15

4 0
3 years ago
What is the product 3x+2+5X
julia-pushkina [17]

Answer:

8x+2

Step-by-step explanation:

Combine Like Terms:

=3x+2+5x

=(3x+5x)+(2)

=8x+2

Hope this helps

5 0
3 years ago
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Find the equation of the linethe line passes through the points (5,2) and (-4,-4)
almond37 [142]

Answer:

y =  \frac{2}{3}x -  \frac{4}{3}

Step-by-step explanation:

first find the slope using the above points then use the slope formula to calculate the slope

m =  \frac{y2 - y1}{x2 - x1}  \\  \frac{2 - -  4}{5 -  - 4}  =  \frac{2 + 4}{5 + 4}  =  \frac{6}{9}  =  \frac{2}{3}

substitute ⅔ for m and one of the above points into the y-intercept form of the equation for a line and solve for b

y = mx + b \\ 2 =  \frac{2}{3} (5)  + b \\ 2 =  \frac{10}{3}  + b \\ 2 -  \frac{10}{3}  = b \\  \frac{6}{3}  -  \frac{10}{3}  = b \\ b =  -  \frac{4}{3}

substitute the slope and the value for b into the equation to get the answer

y =   \frac{2}{3} x -  \frac{4}{3}

4 0
3 years ago
A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t
Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be F=L+2W.

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

LW=80,000...(1)

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be C=20L+5(2W)\Rightarrow 20L+10W.

From equation (1), we will get:

L=\frac{80,000}{W}

Upon substituting this value in cost equation, we will get:

C=20(\frac{80,000}{W})+10W

C=\frac{1600,000}{W}+10W

C=1600,000W^{-1}+10W

To minimize the cost, we need to find critical points of the the derivative of cost function as:

C'=-1600,000W^{-2}+10

-1600,000W^{-2}+10=0

-1600,000W^{-2}=-10

-\frac{1600,000}{W^2}=-10

-10W^2=-1,600,000

W^2=160,000

\sqrt{W^2}=\pm\sqrt{160,000}  

W=\pm 400

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

C''=-2(-1600,000)W^{-3}

C''=3200,000W^{-3}

C''=\frac{3200,000}{W^3}

Now, we will substitute W=400 in 2nd derivative as:

C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05

Since 2nd derivative is positive at W=400, therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting W=400 in L=\frac{80,000}{W}, we will get:

L=\frac{80,000}{400}\\\\L=200

Therefore, the side parallel to the river will be 200 feet.

4 0
3 years ago
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