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Viktor [21]
2 years ago
5

Select the correct choice that completes the sentence below.

Mathematics
2 answers:
vodomira [7]2 years ago
4 0

\sf \red⇛ \green {3a + 1 = 16}

Move the constant to the right-hand side and change its sign to minus sign since it is in plus

\sf \red⇛ \green{3a = 16 - 1}

Subtract the numbers

\sf\red ⇛ \green{3a = 15}

Divide both sides of equation by 3

\sf \red⇛ \green{a = 5}

  • On observing the above steps, Option B is correct!
  • <em>First</em><em> </em><em>step</em><em> </em><em>is</em><em> </em><em>subtraction</em><em> </em><em>then</em><em> </em><em>division</em>
Trava [24]2 years ago
3 0

Step-by-step explanation:

first we arrange the equation properly

secondly 3a=16-1 or 3a=16-1=15

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What is 123 round to the nearest hundered
irina1246 [14]
123 rounded to the nearest hundred is 100 i believe
8 0
3 years ago
Read 2 more answers
What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Radda [10]

Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± \sqrt{-1} = ± i ( noting that \sqrt{-1} = i ), and

x² = - 5 ( take the square root of both sides )

x = ± \sqrt{-5} = ± \sqrt{5(-1)} = ± \sqrt{5} × \sqrt{-1} = ± i\sqrt{5}

Solutions are x = ± i and x = ± i\sqrt{5}

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=9%5Cfrac%7B1%7D%7B2%7D%20%3D%5Csqrt%5B3%5D%7B9%7D" id="TexFormula1" title="9\frac{1}{2} =\sqrt
Gelneren [198K]

Step-by-step explanation:

This isn't. a true identity.

{9}^{ \frac{1}{2} }   doesnt \: equal \:  \:   {9}^{ \frac{1}{3} }

3 0
2 years ago
PLease Help! I'm hopeless at math.
Furkat [3]

Answer:

It's B, I'm only trying my best since there is no picture.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
13. Which system of inequalities has no solution?
Anit [1.1K]

Answer:

Option A

Step-by-step explanation:

We have y < 2x - 4 and y > 2x + 1.

=> 2x - 4 > 2x + 1

=> -4 > 1

Since this inequality is false for all real values of x, there is no solution for the system of inequalities.

8 0
3 years ago
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