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4 years ago

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The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t

hese triangles?

1 answer:

BaLLatris [955]4 years ago

7 0

Answer:

Perimeter of first triangle = 102.73

Perimeter of 2nd triangle = 123.27

Step-by-step explanation:

Dividing the area of two triangle we can find the square of the scale factor:

$\frac{72}{50}$ = 1.44

Scale factor will become = $\sqrt{1.44}$ = 1.2

Sum of perimeter of triangle = 226dm

perimeter of triangle = x + y + z = p

perimeter of first triangle = 1.2(x + y + z) = 1.2p

perimeter of 2nd triangle = (x + y + z) = p

Permieter of first triangle + Perimeter of second triangle = 226

1.2(p) + p = 226

2.2p = 226

p = 102.73 // This is the perimeter of 2nd triangle

For finding permieter of first triangle, multiply it with 1.2

102.7 * 1.2 = 123.27 // This is the perimeter of 1st triangle

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Answer:

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Step-by-step explanation:

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3 years ago

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New cordinates are formed by adding 7 in x and subtracting 2 from y
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3 years ago

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Answer:

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Step-by-step explanation:

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Required

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Distance (d) is calculated using:

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$A = (-2,2)$ --- $(x_1,y_1)$

$B = (1,2)$ --- $(x_2,y_2)$

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