Question

The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of these triangles?

Answer 1

Answer:

Perimeter of first triangle = 102.73

Perimeter of 2nd triangle = 123.27

Step-by-step explanation:

Dividing the area of two triangle we can find the square of the scale factor:

$\frac{72}{50}$  = 1.44

Scale factor will become = $\sqrt{1.44}$ = 1.2

Sum of perimeter of triangle = 226dm

perimeter of triangle = x + y + z = p

perimeter of first triangle = 1.2(x + y + z) = 1.2p

perimeter of 2nd triangle = (x + y + z) = p

Permieter of first triangle + Perimeter of second triangle = 226

1.2(p) + p = 226

2.2p = 226

p = 102.73 // This is the perimeter of 2nd triangle

For finding permieter of first triangle, multiply it with 1.2

102.7 * 1.2 = 123.27 // This is the perimeter of 1st triangle