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AlladinOne [14]
3 years ago
11

Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the r

ule (x−3, y+4) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.
Mathematics
1 answer:
Mademuasel [1]3 years ago
8 0
New cordinates are formed by adding 7 in x and subtracting 2 from y
A(−2, 2) =A ' (-2 +7 , 2 - 1 ) = A' (5,1)
B(−2, 4)  = B' (-2 + 7 , 4 -1 )= B' (5,3)
C(2, 4)   =  C' (2 + 7 , 4 -1 )= C' (9,3)
<span>D(2, 2)   D' (2 + 7 , 2 -1 ) = D' ( 9 , 1)</span><span>

</span>
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Convert: 6y + y² = x² from rectangular to polar form.
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\bf \textit{Double Angle Identities}&#10;\\ \quad \\&#10;sin(2\theta)=2sin(\theta)cos(\theta)&#10;\\ \quad \\\\&#10;cos(2\theta)=&#10;\begin{cases}&#10;\boxed{cos^2(\theta)-sin^2(\theta)}\\&#10;1-2sin^2(\theta)\\&#10;2cos^2(\theta)-1&#10;\end{cases}\\\\\\&#10;tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\&#10;-------------------------------\\\\

\bf 6y+y^2=x^2\implies \cfrac{6y}{x^2}+\cfrac{y^2}{x^2}=1\implies \cfrac{6rsin(\theta )}{[rcos(\theta )]^2}+\cfrac{[rsin(\theta )]^2}{[rcos(\theta )]^2}=1&#10;\\\\\\&#10;\cfrac{6rsin(\theta )}{r^2cos^2(\theta )}+\cfrac{r^2sin^2(\theta )}{r^2cos^2(\theta )}=1\implies &#10;\cfrac{6sin(\theta )}{rcos^2(\theta )}+\cfrac{sin^2(\theta )}{cos^2(\theta )}=1

\bf \cfrac{6sin(\theta )}{rcos^2(\theta )}=1-\cfrac{sin^2(\theta )}{cos^2(\theta )}\implies \cfrac{6sin(\theta )}{1-\frac{sin^2(\theta )}{cos^2(\theta )}}=rcos^2(\theta )&#10;\\\\\\&#10;\cfrac{6sin(\theta )}{cos^2(\theta )\left[ 1-\frac{sin^2(\theta )}{cos^2(\theta )} \right]}=r\implies \cfrac{6sin(\theta )}{cos^2(\theta )-sin^2(\theta )}=r&#10;\\\\\\&#10;\cfrac{6sin(\theta )}{cos(2\theta )}=r
5 0
3 years ago
The ratio of tulips to other flowers in a garden is 3:5. What percent of the flowers in the garden at tulips.
Lyrx [107]
62.5 is the correct answer :)
4 0
3 years ago
Read 2 more answers
Forensic scientists can estimate the overall height of an adult male based on the length of the femur bone. A femur bone that is
faust18 [17]

Answer:

h = 1.88f + 32.01

Step-by-step explanation:

To find the linear equation, we first find the gradient of the linear equation from

(y₂ - y₁)/(x₂ - x₁) = m and using the values of the length of femur and overall height respectively, where x₁ = 18 inches and y₁ = 65.85 inches and x₂ = 14 inches and y₂ = 58.33 inches

So, (y₂ - y₁)/(x₂ - x₁) = m

(58.33 - 65.85)/(14 - 18) = m

-7.52/-4 = m

m = 1.88

So, to find the linear equation, we use

(y - y₁)/(x - x₁) = m where f₁ = 18 inches and h₁ = 65.85 inches

So, (y - y₁)/(x - x₁) = m

(y - 65.85)/(x - 18) = 1.88

(y - 65.85) = 1.88(x - 18)

y - 65.85 = 1.88x - 33.84

collecting like terms, we have

y = 1.88x - 33.84 + 65.85

y = 1.88x + 32.01

Given that y = h = overall height of adult male and x = f = length of femur,

h = 1.88f + 32.01

6 0
3 years ago
A number cube was rolled as part of an experiment. The results are displayed in the table below. What is the best explanation of
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Answer:

The outcome table was not given. But find below how to find the experimental probability

Step-by-step explanation:

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4 0
3 years ago
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The YMCA lap pool is a right rectangular prism 36.8\, \text{m}36.8m36, point, 8, start text, m, end text long by 20 \,\text{m}20
PilotLPTM [1.2K]

Volume is a three-dimensional scalar quantity. The depth of the YMCA lap pool is 2 meters.

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A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Given that the following details about the YMCA lap pool:

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Since the pool is in the space of a right rectangular prism, therefore, the volume of the prism will be the product of length, width and depth. Therefore, the volume of the pool can be written as,

The volume of the pool = Length × width × depth

1472m³ = 36.8m × 20 m × depth of the pool

Depth of the pool = (1472m³ ) / (36.8m × 20m)

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Hence, the depth of the YMCA lap pool is 2 meters.

Learn more about Volume here:

brainly.com/question/13338592

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3 0
1 year ago
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