![\bf \textit{volume of a cube}\\\\ V=s^3~~ \begin{cases} s=\stackrel{\textit{length of}}{\textit{a side}}\\[-0.5em] \hrulefill\\ V=7 \end{cases}\implies 7=s^3\implies \sqrt[3]{7}=s](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cube%7D%5C%5C%5C%5C%20V%3Ds%5E3~~%20%5Cbegin%7Bcases%7D%20s%3D%5Cstackrel%7B%5Ctextit%7Blength%20of%7D%7D%7B%5Ctextit%7Ba%20side%7D%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20V%3D7%20%5Cend%7Bcases%7D%5Cimplies%207%3Ds%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B7%7D%3Ds)
now, Check the picture below, since it's really just 6 square faces,
![\bf \textit{surface area of a cube}\\\\ SA=6s^2~~ \begin{cases} s=\stackrel{\textit{length of}}{\textit{a side}}\\[-0.5em] \hrulefill\\ s = \sqrt[3]{7} \end{cases}\implies SA=6\sqrt[3]{7}\implies SA\approx 11.477587](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bsurface%20area%20of%20a%20cube%7D%5C%5C%5C%5C%20SA%3D6s%5E2~~%20%5Cbegin%7Bcases%7D%20s%3D%5Cstackrel%7B%5Ctextit%7Blength%20of%7D%7D%7B%5Ctextit%7Ba%20side%7D%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20s%20%3D%20%5Csqrt%5B3%5D%7B7%7D%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D6%5Csqrt%5B3%5D%7B7%7D%5Cimplies%20SA%5Capprox%2011.477587)
Let X={a,b,c,3,4,5) and Y = {b,d,f,3,5,7).
insens350 [35]
Answer:
{a,b,c,d,f,3,4,5,7}
Step-by-step explanation:
If X={a,b,c,3,4,5}
Y={b,d,f,3,5,7}
THEREFORE {XUY}= {a,b,c,d,f,3,4,5,7}
577.2 ÷ 65 = 88.8 × 100 = 888
The answer would be 100.
Q. how many factors does 15 have?
1, 3, 5, 15 so 15 has 4 factors
The answer is
b= 28/5 or 5.6 in decimal form