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konstantin123 [22]
3 years ago
14

What are the coordinates of vertex A of square ABCD?

Mathematics
2 answers:
charle [14.2K]3 years ago
6 0

Answer:

D

Step-by-step explanation:

bonufazy [111]3 years ago
5 0
ABCD is a square . if the coordinates of three of its vertices are A(-1,2a), B(a,2a), C(a,0), find the coordinates of D. BC is obviously 2a (it's a vertical line) then AB must be 2a (notice AB is horizontal) so BC = AC because it is a square 2a = a+1 a=1
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Answer ASAP, Will give brainliest
erastova [34]

Answer:

Step-by-step explanation:

1) ABCD is a trapezium. AB ║ CD

∠ADC + ∠DAB  = 180°  { Co interior angles}

110° + ∠DAB = 180

         ∠DAB = 180 -110

∠DAB = 70°

2) Sum of all angles of trapezium = 360°

∠A + ∠B + ∠DCB + ∠D = 360

70° + 50° + ∠DCB + 110° = 360

                 230 + ∠DCB = 360

                            ∠DCB = 360 - 230

∠DCB = 130°

3) For finding the height, use Pythagorean theorem

height² + base² = hypotenuse²

      height² + 6² = 10²

      height² + 36 =100

               height² = 100 - 36

              height² = 64

               height = √64

height = 8 m

4) a = AB = x m

  b = 9 m

h = height = 8 m

Area of trapezium = 120 m²

\frac{(a+b)*h}{2}\\\\  = 120

\frac{(x+9)*8}{2} =120\\\\\\(x +9)*4 = 120

x + 9 = 120/4

x + 9 = 30

    x = 30 - 9

x = 21 m

AB = 21m

                             

7 0
3 years ago
Describe the possible values for x and y when ∣x − y ∣ > 0. What does it mean when ∣x − y ∣ = 0? Can ∣x − y ∣ < 0? Explain
Vilka [71]
The possible values for | x-y | > 0 is any number above 0. x must be greater than y. When | x-y | = 0, That means that x and y are equal to each other. | x-y | can not be less than 0, but it can equal 0.

Hope that this helped!
4 0
3 years ago
Solve for x in the equation X2-8x+41 = 0 -
djverab [1.8K]

Answer:

The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D  

Step-by-step explanation:

Given equation as :

x² - 8 x + 41 = 0

For quadratic equation  ax² + b x + c = 0

The value of x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

∴ For equation x² - 8 x + 41 = 0

Or,                x = \frac{8\pm \sqrt{-8^{2}-4\times 1\times 41}}{2\times 1}

Or,                x = \frac{8\pm \sqrt{-100}}{2}

Or,                x = \frac{8\pm 10i}{2}

∴                  x = ( 4 + 2 i ) , ( 4 - 2 i )

Hence The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D     Answer

7 0
3 years ago
A number is the 1/5 of another number. The sum of both is equal to 78. Which is the highest number out of both numbers?
Reika [66]
D.

1/5 of 65 is

65 × 1 / 5
65 / 5
= 13

65 and 13 add up to 78.

65 is the highest number out of both numbers.


♧
4 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdt%7D%20%3Dky" id="TexFormula1" title=" \frac{dy}{dt} =ky" alt=" \frac
sladkih [1.3K]

This ODE is separable; we have

\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt

Integrating both sides gives a general solution of

\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}

B is the only choice that is applicable.

4 0
3 years ago
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