All categories

4 years ago

216q^3+15q^3 please help me solve it

Mathematics

2 answers:

LuckyWell [14K]4 years ago

8 0

Answer:

231q^3

Step-by-step explanation:

katrin [286]4 years ago

3 0

Answer:

231q^3

Step-by-step explanation:

Just add them together. They have the same expressions. Whenever you see a number with an ending similarly to another such as 3x and 2x, they can add together.

This is no different. If something is 6x^2 and another is 7x^2, you would add them to get 13x^2.

You might be interested in

Ed is drawing plans for a rectangular area. In Ed's plan the play area is 14 feet by 14 feet .True or false the area is 196 squa

Molodets [167]

Answer:DON'T KNOW SO DON'T LOOK AT ME

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

PLZZ HELP ME I NEED ANSWERRS ASAP the number of words x that tina can type per minute is at least 50. write and graph an inequal

swat32

I think it is C hope that helped

8 0

3 years ago

Read 2 more answers

A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain

AysviL [449]

Answer:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

Step-by-step explanation:

For this case we have the following value:

$R = 0.0498 \frac{Kpa}{Km}$

We can convert this first to $\frac{Kpa}{m}$ like this:

$R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}$

Now we use the fact the the pressure is defined as $P =\frac{F}{A}$ , whre P is the pressure, F the force and A the area, so then $Kpa= \frac{KN}{m^2}$ and then we can replace this:

$R=0.0000498 \frac{KN}{m^3}$

Now from definition of work we know that $W= Fd$ where W is the work, F the force and d the distance, so then is equivalent $KN =\frac{KJ}{m}$

And if we replace this into the equation we got:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

4 0

4 years ago

A statistics instructor believes that fewer than 20% of Evergreen Valley College (EVC) students attended the opening night midni

Alex17521 [72]

Answer: It is believed that exactly 20% of Evergreen Valley college students attended the opening night midnight showing of the latest harry potter movie.

Step-by-step explanation:

Since we have given that

n = 84

x = 11

So, $\hat{p}=\dfrac{x}{n}=\dfrac{11}{84}=0.13$

p = 0.20

So, hypothesis:

$H_0:p=\hat{p}\\\\H_a:\hat{p}$

so, test statistic value would be

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.13-0.20}{\sqrt{\dfrac{0.2\times 0.8}{84}}}\\\\z=-1.604$

At 1% level of significance, critical value would be

z= 2.58

Since 2.58>-1.604

So, We will accept the null hypothesis.

Hence, It is believed that exactly 20% of Evergreen Valley college students attended the opening night midnight showing of the latest harry potter movie.

4 0

3 years ago

Read 2 more answers

katie has 4 grapes candies and 3 cherries candies. The ratio of the number of grapes candies to the total number of candie is

Tom [10]

Answer: 7 I think its adding but if its multiplying it is 12

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

216q^3+15q^3 please help me solve it​

216q^3+15q^3 please help me solve it