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3 years ago

Name the angle below 4 different ways. plz help and NO BS answers.

Mathematics

2 answers:

11111nata11111 [884]3 years ago

6 0

Angle 1
Angle BAC
Angle CAB
Angle A

Ostrovityanka [42]3 years ago

3 0

They are BAC, CAB, ABC, and BCA

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Keisha solved the following equation: 4x − 2x + 8 = 6(x + 4) Step Work Justification 1 2x + 8 = 6(x + 4) Combine like terms 2 2x

kolbaska11 [484]

4x - 2x + 8 = 6(x + 4) Given

(4x - 2x) + 8 = 6(x + 4)

2x + 8 = 6(x + 4) Combine like terms

2x + 8 = (6)(x) + (6)(4)

2x + 8 = 6x + 24 Distributive Property

2x - 6x + 8 = 6x - 6x + 24

-4x + 8 = 24 Subtraction Property of Equality

-4x + 8 - 8 = 24 - 8

-4x = 16 Subtraction Property of Equality

-4x : (-4) = 16 : (-4)

x = -4 Division Property of Equality

4 0

4 years ago

A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4

vlabodo [156]

Answer:

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

Step-by-step explanation:

Bernoulli's equation,

$P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2$

P₁ = P₂= atmospheric presser

$\rho$ = density

$\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2$ [since P₁ = P₂]

$\Rightarrow\rho (\frac12 v^2_1+ g h_1)= \rho(\frac12 v^2_2+ g h_2)$

$\Rightarrow\frac12 v^2_1+ g h_1= \frac12 v^2_2+ g h_2$

$\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2$

$\Rightarrow v^2_2- v^2_1=2g h$ [ $h_1-h_2=h$ ]

Here $v_1\approx 0$

$\Rightarrow v^2_2=2g h$

$\therefore v_2=\sqrt {2gh$

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole $v_2$ = $\sqrt {2\times 9.8\times 10.4}$ m/s

=14.28 m/s.

Given, the rate of flow from the leak is $2.53\times 10^{-3}$ $m^3/min$

$=\frac{2.53\times 10^{-3}}{60}$ $m^3/s$

Let the diameter of the hole be d.

Then the cross section area of the hole is $=\pi (\frac d2)^2$

We know that,

The rate of flow = Cross section area × speed

$\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28$

$\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}$

$\Rightarrow d= 1.94 \times 10^{-3}$

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

4 0

4 years ago

16 and one forth evaluated

MariettaO [177]

16 1/4
=65/4
you knowwwwww

3 0

3 years ago

Read 2 more answers

All the members of a construction crew work at the same pace. Four of them working together are able to pour concrete foundation

Mnenie [13.5K]

Answer:

Step-by-step explanation:

Please find attachment for step by step explanation.

5 0

3 years ago

A baby weighed 7.25 pounds at birth. At the end of 8 months, the baby weighed 212

Vinil7 [7]

Answer:

1537pounds

Step-by-step explanation:

Given parameters:

Weight of baby at birth = 7.25 pounds

Unknown:

Weight at the end of 8months = ?

Solution:

From the second sentence;

Weight at the end of the eighth month = 212 x weight at birth.

Input the parameters and solve;

Weight at the end of eighth month = 212 x 7.25 = 1537pounds

7 0

4 years ago