Answer:
No, the points are in a linear pattern.
Step-by-step explanation:
Residual plot is a graph that shows the residuals on the vertices. The y-axis has residual values and x-axis has independent variables. The horizontal axis shows the independent variables to determine the best fit for a set. The graph given is in a linear pattern. The random pattern shows that linear model is good fit.
The correct equation of the scaled figure is given by 6/3 = 4/a
<h3>Scaling</h3>
Scaling is the process of either increasing or decreasing the size of a figure by a factor.
From the diagram attached, Figure f is a scaled copy of Figure e. Figure e is decreased to produce figure f, hence:
- AB/XY = CD / WZ
- 6/4 = 3 / a
- 6/3 = 4/a
The correct equation of the scaled figure is given by 6/3 = 4/a
Find out more on scaling at: brainly.com/question/10253650
The poster is a rectangle.
P = 2 L + 2 W
where L is the length and W is the width of a rectangle.
L = W + 2 1/2 = W + 2.5
103 = 2 ( W + 2.5 ) + 2 W
103 = 2 W + 5 + 2 W
103 = 4 W + 5
4 W = 103 - 5
4 W = 98
W = 98 : 4
W = 24.5 in
L = 24.5 + 2.5
L = 27 in
Answer:
The poster is 27 inches long and 24.5 inches wide.
Answer:
Step-by-step explanation:
Given that in an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin, and a second group was given a placebo. A sample consisting of 50 women who received aspirin has mean arterial blood pressure 120mmHg and standard deviation 10mmHg; a sample of 42 women who were given the placebo has mean blood pressure 115mmHg and standard deviation 12mmHg.
Population variances are equal
(two tailed test at 5% significance level)
Here x denotes group I and Y group II
N Mean StDev SE Mean
Sample 1 50 120 10 1.4142
Sample 2 42 115 12 1.8516
Pooled std deviation = 10.9565
df=80
Mean difference= 5
Test statistic t = mean diff/std error = 
=2.1803
p value = 0.0318
since p <0.05 we reject H0
b) We find p >0.01 hence at 1% significance level we accept H0
This implies that 99% confidence interval contains mean difference =0
Answer:
a. true
b. true
c. True
Step-by-step explanation:
a. The domain of a relation includes all possible set of data that are the x-values. Therefore, the domain of the relationship given would be: {2, 3, 5, 6}.
a is True.
b. The range includes all corresponding y-values. Therefore,
Range would be {1 4, 5, 7}
b is Tire.
c. There's 5 on both range and domain.
c is hungry.
