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3 years ago

If you are delt 4 cards from shuffled deck of 52 cards, find the probability that all 4 cards are diamonds

1 answer:

7 0

P(first diamond) = 13/52
P(second diamond) = (13-1)/(52-1) = 12/51
P(third diamond) = (13-2)/(52-2) = 11/50
P(fourth diamond) = (13-3)/(52-3) = 10/49
To get all four diamonds, multiply together the four probabilities to get
P(four diamonds)=13/52*12/51*11/50*10/49=11/4165

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At a manufacturing plant where switches are made, it is a known fact that 2% of all switches are defective. If two switches are

olchik [2.2K]

Answer:

The probability that exactly one switch is good is

$P(x) =0.0392$

Step-by-step explanation:

The probability that a switch is defective is:

$P(D) = \frac{2}{100} =0.02$

The probability that a switch is not defective is

$P(D') = 1-P(D)=0.98$

Therefore, if two switches are selected, the probability that exactly 1 is good is:

$P(1=1)=P (D) P (D ') + P (D') P (D)$

$P(x)=(0.02)(0.98) + (0.98)(0.02)$

$P(x) =0.0392$

6 0

3 years ago

Read 2 more answers

Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is

pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0

2 years ago

my yearly income is 18,000. My medical insurance premium is 230 a month. Is my medical premium 9.66% less then yearly income?

JulijaS [17]

NO.....9.66% less than $18,000 is $16,261.20
230×12= $2,760

7 0

2 years ago

Find the value of x? x=????

AnnyKZ [126]

Answer:

15.5

Step-by-step explanation:

The plus of two angles in the picture are 90 degrees: 37° + 53°

8 0

3 years ago

The currency in Sweden is the kroner. The exchange rate is approximately $1 for 7 Kroner. At this rate how many kroner would you

solmaris [256]

14 kroner because 7×2 is 14 and the 2 if from the $2

3 0

3 years ago

Read 2 more answers