All categories

3 years ago

Which graph represents the solution to this inequality

Mathematics

2 answers:

12345 [234]3 years ago

5 0

Answer:

Step-by-step explanation:

$-\frac{1}{4}(12x+8)\leq -2x+11\\\\-\frac{1}{4}*12x+\frac{-1}{4}*8)\leq -2x+11\\\\-3x-2\leq -2x+11$

Add 3x to both sides

-2 ≤ -2x + 11 + 3x

-2 ≤ x + 11

Subtract 11 from both sides

-2-11 ≤ x + 11 -11

-13 ≤ x

X should be greater than or equal to -13

x ={-13, -12 , -11 , -10,..........}

Dimas [21]3 years ago

4 0

Answer:

Your answer is c

Step-by-step explanation:

First add two to both sides of equation:

-3x -2 + 2 ≤ - 2x + 11 + 2

Then simplify,

-3x ≤ -2x + 13

Then add 2x to both sides :

-3x + 2x ≤ - 2x + 13 + 2x

Simplify again,

-x ≤ 13

Reverse the inquality:

X ≥ - 13

Then graph it which I can't do right now but your answer will turn out to be c.

Hope this help, and have a good day! :)

(Brainliest would be appreciated)?

You might be interested in

Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.

Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; $x = \frac{2+3\sqrt{2}}{2}$ ; $x = \frac{2-(3)\sqrt{2}}{2}$

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the following condition must be followed:

Either (x² − 6x +3) = 0 ............(1)

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

for the equation ax² + bx + c = 0

thus,

the roots are

$x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}$

$x = \frac{6\pm\sqrt{36-12}}{2}$

$x = \frac{6+\sqrt{24}}{2}$ and, x = $x = \frac{6-\sqrt{24}}{2}$

$x = \frac{6+2\sqrt{6}}{2}$ and, x = $x = \frac{6-2\sqrt{6}}{2}$

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

$x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}$

$x = \frac{4\pm\sqrt{16+56}}{4}$

$x = \frac{4+\sqrt{72}}{4}$ and, x = $x = \frac{4-\sqrt{72}}{4}$

$x = \frac{4+\sqrt{2^2\times3^2\times2}}{2}$ and, x = $x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}$

$x = \frac{4+(2\times3)\sqrt{2}}{2}$ and, x = $x = \frac{4-(2\times3)\sqrt{2}}{4}$

$x = \frac{2+3\sqrt{2}}{2}$ and, $x = \frac{2-(3)\sqrt{2}}{2}$

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; $x = \frac{2+3\sqrt{2}}{2}$ ; $x = \frac{2-(3)\sqrt{2}}{2}$

7 0

2 years ago

Whats the equation of the line that passes threw -4,4 and is parrell to the line y=1/2-4

vovangra [49]

Answer:

$y=\frac{1}{2}x+6$

Step-by-step explanation:

Given:

The equation of the known line is:

$y=\frac{1}{2}x-4$

A point on the unknown line is (-4, 4)

Now, since the two lines are parallel, their slopes must be equal.

Now, slope of the known line is the coefficient of 'x' which is $\frac{1}{2}$ .

Therefore, the slope of the unknown line is also $m=\frac{1}{2}$

Now, for a line with slope 'm' and a point on it $(x_1,y_1)$ is given as:

$y-y_1=m(x-x_1)$

Here, $m=\frac{1}{2}, x_1=-4,y_1=4$ . Therefore,

$y-4=\frac{1}{2}(x-(-4))\\\\y-4=\frac{1}{2}(x+4)\\\\y-4=\frac{1}{2}x+2\\\\y=\frac{1}{2}x+2+4\\\\y=\frac{1}{2}x+6$

Hence, the equation of the unknown line is $y=\frac{1}{2}x+6$ .

5 0

3 years ago

Solve the inequality 2x - 3 < x + 2 ≤ 3x + 5. Show your work.?

mars1129 [50]

Add like terms and put x in the middle.
-3 < -2x + x - 3x ≤ 5 - 2
-3 < - 4x ≤ 3
Sign changed when divide by negative numbers
(3/4) > x ≥ (-3/4)

4 0

3 years ago

I 216 Solve the linear equation. 9x - 9 = 5x + 19 x=-7 x = 7 x = 5 x = 2

const2013 [10]

Answer:

x=7

Step-by-step explanation:

9x-9=5x+19

Combine like terms

9x-5x=19+9

4x=19+9

4x=28

x=7

5 0

3 years ago

Evaluate each of the following x=5 (5x-3)/2 (10-6)/5

Talja [164]

Answer:

4/5

Step-by-step explanation:

there u go thats quick maths

7 0

2 years ago

Which graph represents the solution to this inequality ​

Which graph represents the solution to this inequality