Answer:
That it is time for lunch?
Explanation:
I guess the answer in the blank is processes.
Activities called processes involve the microprocessor receiving commands as software carries out tasks and while input arrives from the keyboard, mouse, and other devices.
Answer:
public static void printDottedLine()
{
System.out.println(".....");
}
Explanation:
The above written code is in JAVA and it is the method definition of the method mentioned in the question.Since the method returns nothing hence it's return type is void and it does not have any arguments hence there is nothing written in the parenthesis.In JAVA System.out.println is used for standard output and trminates them by newline.
Answer: True
Explanation:
Subset sum problem and Knapsack problem can be solved using dynamic programming.
In case of Knapsack problem there is a set of weights associative with objects and a set of profits associated with each object and a total capacity of knapsack let say C. With the help of dynamic programming we try to include object's weight such that total profit is maximized without fragmenting any weight of objects and without exceeding the capacity of knapsack, it is also called as 0/1 knapsack problem.
Similar to knapsack problem, in subset sum problem there is set of items and a set of weights associated with the items and a capacity let say C, task is to choose the subset of items such that total sum of weights associated with items of subset is maximized without exceeding the total capacity.
On the basis of above statements we can say that subset sum problem is generalization of knapsack problem.
Answer:
#include <iostream>
using namespace std;
void PrintPopcornTime (int bagOunces){
if (bagOunces < 2){
cout << "Too small"<<endl;
}
else if (bagOunces > 10){
cout << "Too large"<<endl;
}
else{
cout << bagOunces*6 <<" seconds"<<endl;
}
}
int main(){
PrintPopcornTime(7);
return 0;
}
Explanation:
Create a function called PrintPopcornTime that takes one parameter, bagOunces
Check the bagOunces using if-else structure. If it is smaller than 2, print "Too small". If it is greater than 10, print "Too large". Otherwise, calculate and print 6*bagOunces followed by " seconds".
Call the function in the main function with parameter 7. Since 7 is not smaller than 2 or not greater than 10, "42 seconds" will be printed.
