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Dahasolnce [82]
2 years ago
8

An optical fibre has an attenuation of 0.3 dB/km. If a laser launches an optical power level of PIN (mW) into 35 km length of th

is fibre, at what distances will the power have dropped to:
(a) 75%

(b) 50%

(c) 25%

(d) 12.5%

(e) 6.25%

of the input power level? Plot these points on a graph of P IN/P OUT versus distance along the fibre.
Computers and Technology
1 answer:
REY [17]2 years ago
6 0
I think it’s 75% sorry if it’s wrong :(
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The answer would be 13.3125 because 6.25 / 0.8 is 7.8125 than add 5.5 which will equal 13.3125. I'm sure about this.
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This is for C++: Using a nested for loop output the following pattern to the screen:
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Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int r=26,x,y;//defining integer variable  

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for(x= 1; y<= r; x++)//using for loop for count value

{

for(y= 1; y<= x; y++)//using for loop to convert value in triangle  

{

c=(char)(y+64);//convert value into character  

cout << c;//print character value

}

cout << "\n";//use print method for line break

}

return 0;

}

Output:

Please find the attachment file.

Explanation:

In this code, three integer variable "x,y, and r", and one character variable "c" is declared, that is used in the nested for loop,  in the first for loop it counts the character value and in the next for loop, it converts the value into a triangle and uses the char variable to print its character value.

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A stack is initially empty, then the following commands are performed: push 5, push 7, pop, push 10, push 5, pop, which of the f
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d

Explanation:

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This unit is used to print the picture on a paper
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Answer:a printer

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Q1). Write a python program to pass a list to a function and double the odd values and half even values of a list and display li
zepelin [54]

Answer:

\textsf{\large{\underline{Solution}:}}

The given problem is solved using language - Python.

def f(x):

   new_list=[]

   for i in x:

       if i%2==0:

           new_list.append(i//2)

       else:

           new_list.append(i*2)

   return new_list

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(my_list)

print('Modified List:',my_list)

\textsf{\large{\underline{Logic}:}}

  1. Create a new list.
  2. Iterate over the list passed into the function.
  3. Check if the element is even or not. If true, append half the value of element in the list.
  4. If false, append twice the value of the element in the list.
  5. At last, return the new list.

There is another way of doing this - By using map() function.

—————————————————————————————

def f(x):

   return list(map(lambda x:x//2 if x%2==0 else 2*x,x))

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(2my_list)

print('Modified List:',my_list)

—————————————————————————————

\textsf{\large{\underline{O{u}tput}:}}

Original List: [1, 2, 3, 4, 5]

Modified List: [2, 1, 6, 2, 10]

8 0
2 years ago
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