The coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
<h3>What are the coordinates of the vertices of the image?</h3>
The vertices of the preimage of the triangle are given as:
L = (4, -6)
M = (5, -1)
N = (7, -3)
The rotation is given as: 180 degrees counterclockwise
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The rule of this rotation is
(x, y) => (-x, -y)
So, we have:
L' = (-4, 6)
M' = (-5, 1)
N' = (-7, 3)
Hence, the coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
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Answer:
d is the answer
Step-by-step explanation:
perimeter of rect = 2(7+3) = 20
perimeter of square = 4 a =20
a = 5
Answer: the second one
Step-by-step explanation:
Answer:
6647
Step-by-step explanation:
The computation of the advertising revenue for 15 years is shown below:
Given that
r(t) = -18t^2 + 720t - 103
where
t = number of years = 15
now put the value of t in the above equation
= -18(15)^2 + 720(15) - 103
= -4050 + 10,800 - 103
= 6647
x =2 y =8
2x + 2y=20
2x=20-2y
x=10-y
Ahora len la otra ecuacion remplazamos x por (10-y)
-2(10-y)-6y=-52
-20+2y-6y=-52
2y-6y= -32 (-52+20= -32)
-4y=-32
-y=-8
y=8 x=10-y x=2
2*2+2*8=20
4+16=20
-2*2-6*8= -52
-4-48= -52
