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hram777 [196]
2 years ago
8

Solve for n.

Mathematics
2 answers:
natita [175]2 years ago
6 0

Answer:

B. n=7.5

Step-by-step explanation:

if a+b=c then

c-b=a

Temka [501]2 years ago
3 0
Answer: n=7.5
Hope this helps!
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A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
Help me now now plz I’m trying to passssss
wlad13 [49]
I’m sure your answer is D. 180 - 125 will get you 55.!
Have a nice day!
4 0
2 years ago
Mrs. Nelson bought a 2-gallon container
Serjik [45]
128, because it’s actually 256 but 256/ 2= 128
5 0
2 years ago
Read 2 more answers
In a survey of 300 middle school students, 15% said they play sports after school. How many
blsea [12.9K]

Answer:

45

Step-by-step explanation:

15% of 100 = 15

15 x 3 = 45

5 0
3 years ago
Suppose the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1
denis23 [38]
Given that <span>the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces.

The probability of a normally distributed data between two values (a, b) is given by:

P(a\ \textless \  X\ \textless \  b)=P\left(z\ \textless \  \frac{b-\mu}{\sigma/\sqrt{n}} \right)-P\left(z\ \textless \  \frac{a-\mu}{\sigma/\sqrt{n}} \right) \\  \\ =P(7.5\ \textless \ X\ \textless \ 8.5)=P\left(z\ \textless \  \frac{8.5-8.0}{1.1/\sqrt{6}} \right)-P\left(z\ \textless \  \frac{7.5-8.0}{1.1/\sqrt{6}} \right) \\  \\ =P(z\ \textless \ 1.113)-P(-1.113)=0.8672-0.1328=0.7344</span>
6 0
3 years ago
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