Answer:
cost to make paper signs = $1
cost to make laminated signs = $2
Step-by-step explanation:
Let
x = cost to make paper signs
y = cost to make laminated signs
8x + 2y = 12 (1)
10x + 10y = 30 (2)
Multiply (1) by 5
40x + 10y = 60 (3)
10x + 10y = 30 (2)
Subtract (2) from (3) to solve for x
40x - 10x = 60 - 30
30x = 30
x = 30/30
x = $1
Substitute x = 1 into (1)
8x + 2y = 12
8(1) + 2y = 12
8 + 2y = 12
2y = 12 - 8
2y = 4
y = 4/2
y = $2
cost to make paper signs = $1
cost to make laminated signs = $2
Answer: cd(x) = 4x³ — 2x² + 8x — 4
Step-by-step explanation:
c(x) = 4x - 2
d(x) = x² + 2
Therefore, cd(x) = c(x) × d(x)
cd(x) = (4x - 2)(x² + 2)
= (4x × x²) + (4x × 2) + (-2 × x²) + (-2 × 2)
= 4x³ + 8x -2x² - 4
cd(x) = 4x³ — 2x² + 8x — 4
Hope this helps?
Answer:
1
Step-by-step explanation:
To complete the square, first you must make sure that the coefficient of the x^2 term is 1. Here you have x^2 - 2x - 37 = 0. Since the x^2 term is simply x^2, you do have a coefficient of 1 for the x^2 term.
To find the number you need to add to complete the square, take the coefficient of the x term. Divide it by 2. Then square it.
The x term is -2x. The coefficient of the x term is -2.
Take half of -2 which is -1.
Now square -1 to get 1.
You need to add 1 to complete the square.
brainliest?!?!yes
The position function of a particle is given by:
The velocity function is the derivative of the position:
The particle will be at rest when the velocity is 0, thus we solve the equation:
The coefficients of this equation are: a = 2, b = -9, c = -18
Solve by using the formula:
![t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Substituting:
![\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81-4%282%29%28-18%29%7D%7D%7B2%282%29%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81%2B144%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B225%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm15%7D%7B4%7D%20%5Cend%7Bgathered%7D)
We have two possible answers:
We only accept the positive answer because the time cannot be negative.
Now calculate the position for t = 6:
Answer: the correct option is
(D) The imaginary part is zero.
Step-by-step explanation: Given that neither a nor b are equal to zero.
We are to select the correct statement that accurately describes the following product :
We will be using the following formula :
From product (i), we get
![P\\\\=(a+bi)(a-bi)\\\\=a^2-(bi)^2\\\\=a^2-b^2i^2\\\\=a^2-b^2\times (-1)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }i^2=-1]\\\\=a^2+b^2.](https://tex.z-dn.net/?f=P%5C%5C%5C%5C%3D%28a%2Bbi%29%28a-bi%29%5C%5C%5C%5C%3Da%5E2-%28bi%29%5E2%5C%5C%5C%5C%3Da%5E2-b%5E2i%5E2%5C%5C%5C%5C%3Da%5E2-b%5E2%5Ctimes%20%28-1%29~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%5B%5Ctextup%7Bsince%20%7Di%5E2%3D-1%5D%5C%5C%5C%5C%3Da%5E2%2Bb%5E2.)
So, there is no imaginary part in the given product.
Thus, the correct option is
(D) The imaginary part is zero.
