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GREYUIT [131]
3 years ago
14

PLEASE HELP!!!

Mathematics
2 answers:
diamong [38]3 years ago
8 0
DE. AB, is going up BC, isn't decreasing or increasing. CD, isn't decreasing or increasing. Therefore your answer is DE.
LenKa [72]3 years ago
3 0

Answer:

<u>DE </u>

Step-by-step explanation:

The answer is DE because it's going down hill and therefore decreasing.

Hint: When looking at these types of problems try thinking about a bus.

That helps me and I hope this helps you :)

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Solve 5x - c = k for x<br><br> Answers above
Rama09 [41]

Answer:

x = ( k+c)/5

Step-by-step explanation:

5x - c = k

Add c to each side

5x -c+c = k+c

5x = k+c

Divide by 5

5x/5= ( k+c)/5

x = ( k+c)/5

5 0
3 years ago
Read 2 more answers
Which of the following it true about √3x2
nata0808 [166]

Answer:

B)

Step-by-step explanation:

  • Rational number: can be expressed as a ratio of two integers
  • Irrational number: cannot be expressed as a ratio of two integers

\textsf{2 is a rational number as }2=\dfrac21

\sqrt{3} \textsf{ is an irrational number}

2\sqrt{3} \textsf{ is an irrational number}

3 0
2 years ago
Read 2 more answers
Can someone explain (with steps) how to rationalize the following expression?
insens350 [35]
F(x)=(-2/((x+y-2)^(1/2))-(x+y+2)^(1/2)
the only irrational part of this expression is the (x+y-2)^(1/2) in the denominator, so, to rationalize this, you multiply the numerator and denominator by the denominator, as well as the other parts of the expression
also, you must multiply the -sqrt(x+y+2) by sqrt(x+y-2)/sqrt(x+y-2) to form a common denominator
(-2)/(x+y-2)^(1/2)-(x+y+2)^(1/2)(x+y-2)^(1/2)/(x+y-2)^(1/2)
(common denominator)
(-2-(x^2+xy+2x+xy+y^2+2y-2x-2y-4))/(x+y-2)^(1/2)
(FOIL)
(-2-x^2-y^2-2xy+4)/(x+y-2)^(1/2)
(Distribute negative)
(-x^2-y^2-2xy+2)/(x+y-2)^(1/2)
(Simplify numerator)
(-x^2-y^2-2xy+2)(x+y-2)^(1/2)/(x+y-2)^(1/2)(x+y-2)^(1/2)
(Rationalize denominator by multiplying both top and bottom by sqrt)
(-x^2-y^2-2xy+2)((x+y-2)^(1/2))/(x+y-2)
(The function is now rational)
=(-x^2-y^2-2xy+2)(sqrt(x+y-2))/(x+y-2)
6 0
3 years ago
Pls help<br><br> Given: △ABC, CM⊥ AB, BC = 5, AB = 7<br> CA = 4 sqrt(2)<br> Find: CM
babymother [125]

Answer:

The general plan is to find BM and from that CM. You need 2 equations to do that.

Step One

Set up the two equations.

(7 - BM)^2 + CM^2 = (4*sqrt(2) ) ^ 2 = 32

BM^2 + CM^2 = 5^2 = 25

Step Two

Subtract the two equations.

(7 - BM)^2 + CM^2  = 32

BM^2 + CM^2         = 25

(7 - BM)^2 - BM^2 = 7               (3)

Step three

Expand the left side of the new equation labeled (3)

49 - 14BM + BM^2 - BM^2 = 7    

Step 4

Simplify And Solve

49 - 14BM = 7              Subtract 49 from both sides.

-49 - 14BM = 7 - 49

- 14BM = - 42              Divide by - 14

BM = -42 / - 14

BM = 3

Step  Five

Find CM

CM^2 + BM^2 = 5^2

CM^2 + 3^2 = 5^2        Subtract 3^2 from both sides.

CM^2 = 25 - 9            

CM^2 = 16                     Take the square root of both sides.        

sqrt(CM^2) = sqrt(16)

CM = 4    < Answer

Step-by-step explanation:

6 0
3 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
gogolik [260]
Vertical angles are congruent, so their measures are equal.
Set the angle measures equal and solve for x.

2x + 2 = 3x - 52

-x = -54

x = 54

___________
|                      |
|        54         |
|__________|

The answer is inside a box.
3 0
3 years ago
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