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Goshia [24]
3 years ago
6

Graph y=sin^-1 (-1/2x) on the interval -5≤x≤5.

Mathematics
1 answer:
motikmotik3 years ago
6 0

Answer:

Option c.

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

y=sin^-1 (-1/2x)   on the interval -5 ≤ x ≤ 5

Looking at the graph, we can tell that the correct option is

Option c.

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What was the property of equality
loris [4]

Reflexive Property=For all real number X,X=X

A number equals itself

Addition Property=For all real number X,y & Z,. if

X=Y then X+y=y+Z

Subtraction Property=For all real number X,Y And Z if X=y then X-Z=y-Z.

7 0
3 years ago
Drag each term to the correct location on the expression. each term can be used more than once, but not all terms will be used.
grandymaker [24]

Answer:

4(x-3)(x+6)

Step-by-step explanation:

We factor out the 4 first since all numbers are divisible by 4. That leaves us with x^2+3x-18.

Then we factor this to get (x-3)(x+6).

So the factored form of the equation is 4(x-3)(x+6)

8 0
4 years ago
2x2 − 4x = 0<br> A. <br> 0, -4<br> B. <br> 0, -2<br> C. <br> 0, 2<br> D. <br> 2, 4
leonid [27]

Answer:

C

Step-by-step explanation:

We see that we can factor out 2x from the equation! So our equation becomes 2x(x-2) = 0.

Since the only way for things to multiply to equal to zero is if at least one of the numbers is 0.

So if x-2 is the 0, then x = 2.

If 2x is the 0, then x = 0.

So our answer is C. 0,2

5 0
4 years ago
Suppose we draw 3 marbles from a jar containing 7 red and 5 blue marbles. At each stage, a ball is drawn and its color noted. Th
Vilka [71]

Answer:

The probability that the next two balls are blue is \frac{5}{32}

Step-by-step explanation:

There is a total number of 12 balls in the jar (7 Red and 5 blue), if the first marble drawn is a given, that is it is a Red marble, then following the instruction the Red marble and two more Red marbles are added. Therefore making the total number of marbles in the jar to be 14 marbles (9 red and 5 blue).

<u>FIRST EVENT:</u> So the probability of drawing the second marble to be a blue marble becomes = 5/14 [<em>this is the number of blue marbles/ total number of marbles in the jar</em>].

Thereafter the blue marble is returned and two more blue marbles are added to the jar making a total of 16 marbles (9 red and 7 blue}.

<u>SECOND EVENT: </u>So the probability of drawing the third marble to be a blue marble becomes = 7/16 [<em>this is the number of blue marbles/ total number of marbles in the jar</em>].

However, this is not the final answer because the first event and the second event must occur together, therefore, one has to multiply the first events probability and the second events probability to get the probability we are looking for.

So, the probability of picking the next two to be blue = 5/14*7/16 (seven can reduce the 14 to a 2 based on division)

Therefore the probability = 5/32 (the 2 multiplies the 16)

3 0
4 years ago
Please solve this puzzle
Natali5045456 [20]

Answer:

a = 25 m²

b = 5 m

c = 7.94 m

d = 35.73 m²

Code:    H I A B

Step-by-step explanation:

<u>Formulae</u>

Pythagoras’ Theorem:    a^2+b^2=c^2

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

Area of a square = x²  (where x is the side length)

------------------------------------------------------------------------------------------------------

Assuming that all the quadrilaterals are squares.

Side length of blue square with area 16 m² = √16 = 4 m

Side length of yellow square with area 9 m² = √9 = 3 m

Use Pythagoras' Theorem to find the <u>length of b</u>:

\implies 4^2+3^2=b^2

\implies b^2=25

\implies b=\sqrt{25}

\implies b=5\: \sf m

Now we have found length b, we can find <u>area a</u>:

\textsf{Area a}=b^2=5^2=25\: \sf m^2

Side length of purple square with area 144 m² = √144 = 12 m

Side length of green square with area 81 m² = √81 = 9 m

Use Pythagoras' Theorem to find the <u>length of c</u>:

\implies 9^2+c^2=12^2

\implies c^2=63

\implies c=\sqrt{63}

\implies c=3\sqrt{7}

\implies c=7.94\: \textsf{(nearest hundredth)}

Now we have found length d, we can find <u>area d</u>:

\textsf{Area d}=\dfrac{1}{2}(9)(7.94)=35.73\: \sf m^2

Code:    H I A B

3 0
2 years ago
Read 2 more answers
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