Question

Please solve this puzzle

Answer 1

Answer:

a = 25 m²

b = 5 m

c = 7.94 m

d = 35.73 m²

Code:    H I A B

Step-by-step explanation:

Formulae

Pythagoras’ Theorem:    $a^2+b^2=c^2$

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

Area of a square = x²  (where x is the side length)

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Assuming that all the quadrilaterals are squares.

Side length of blue square with area 16 m² = √16 = 4 m

Side length of yellow square with area 9 m² = √9 = 3 m

Use Pythagoras' Theorem to find the length of b:

$\implies 4^2+3^2=b^2$

$\implies b^2=25$

$\implies b=\sqrt{25}$

$\implies b=5\: \sf m$

Now we have found length b, we can find area a:

$\textsf{Area a}=b^2=5^2=25\: \sf m^2$

Side length of purple square with area 144 m² = √144 = 12 m

Side length of green square with area 81 m² = √81 = 9 m

Use Pythagoras' Theorem to find the length of c:

$\implies 9^2+c^2=12^2$

$\implies c^2=63$

$\implies c=\sqrt{63}$

$\implies c=3\sqrt{7}$

$\implies c=7.94\: \textsf{(nearest hundredth)}$

Now we have found length d, we can find area d:

$\textsf{Area d}=\dfrac{1}{2}(9)(7.94)=35.73\: \sf m^2$

Code:    H I A B

Answer 2

Find b

• √16+9
• √25
• 5

#a

Area

• b²
• 5²
• 25m²

H

#b

Done already

• I

#c

• √144-81
• √63
• c=7.94

A

#d

• 1/2(7.94)(9)
• 35.73m²

B

Code is

• HIAB