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fiasKO [112]
3 years ago
12

What is mDFC? 45° 80° 125° 135°

Mathematics
2 answers:
Alex73 [517]3 years ago
6 0
<h2>mDFC degree</h2>

Movement of Democratic Forces of the Casamance  (mDFC ) is 80°. But it could be 45 stil. It  is the chief separatist change in the Casamance area of Senegal, established in 1982. Though, many teams of the MFDC denied to join in the rest contract and resumed their struggle.

andrew-mc [135]3 years ago
4 0
I believe its 80 but it could be 45 still
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Find the measure of C to the nearest degree.
Alisiya [41]

Let the ∠C be : θ

From the figure, We can see that the Side which is opposite to angle θ is measuring 7 units

Also, We can notice that Hypotenuse is 11 units

As we are dealing with opposite and hypotenuse, we can clearly use Sinθ to find out the angle θ

We know that :

\bigstar \ \ \boxed{\sf{Sin\theta = \dfrac{Opposite \ Side}{Hypotenuse}}}

\implies \sf{Sin\theta = \dfrac{7}{11}}

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<u>Answer</u> : The measure of ∠C to the nearest degree is 38°

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3 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
PLEASE HELP ASAP 35 PTS + BRAINLIEST TO RIGHT/BEST ANSWER
Semenov [28]

Answer:

(5,2,2)

Step-by-step explanation:

-3x+4y+2z = -3

2x-4y-z=0

y = 3x-13


Multiply the second equation by 2

2*(2x-4y-z)=0*2

4x -8y -2z =0

Add this to the first equation to eliminate z

-3x+4y+2z = -3

4x -8y -2z =0

-------------------------

x -4y = -3

Take the third equation and substitute it in for y

x - 4(3x-13) = -3

Distribute the 4

x - 12x +52 = -3

Combine like terms

-11x +52 = -3

Subtract 52 from each side

-11x +52-52 = -3-52

-11x = -55

Divide by -11

-11x/-11 = -55/-11

x=5

Now we can solve for y

y =3x-13

y =3*5 -13

y = 15-13

y=2

Now we need to find z

2x-4y-z=0

2(5) -4(2) -z=0

10-8 -z=0

2-z=0

Add z to each side

2-z+z= 0+z

2=z

x=5, y=2, z=2

(5,2,2)

3 0
3 years ago
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