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fiasKO [112]
3 years ago
12

What is mDFC? 45° 80° 125° 135°

Mathematics
2 answers:
Alex73 [517]3 years ago
6 0
<h2>mDFC degree</h2>

Movement of Democratic Forces of the Casamance  (mDFC ) is 80°. But it could be 45 stil. It  is the chief separatist change in the Casamance area of Senegal, established in 1982. Though, many teams of the MFDC denied to join in the rest contract and resumed their struggle.

andrew-mc [135]3 years ago
4 0
I believe its 80 but it could be 45 still
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a dog weighs 44 pounds and the veterinarian thinks it needs to lose 7 pounds. mikala wrote the equation x+7=44 to represent the
Reptile [31]
Weight of the dog in question = 44 pounds
Amount of weight the dog needs to reduce as per the veterinarian = 7 pounds
Let us assume the new weight of the dog in question = x
Then
44 - x = 7
This equation can also be represented as
x + 7 = 44.
So from the above deductions we can say that 44 - x = 7 is the correct equation. Another equation to represent the situation given in the question is x + 7 = 44
8 0
4 years ago
Planet Distance from sun (in km) Distance in scientific notation
Westkost [7]

Answer:

1.5.7909 2. 6.724 3. 9.296 4. 1.416 5. 4.838 6. 1.784 7. 2.793 8. 2.793

Step-by-step explanation: these are the planets in order hope this helps

6 0
3 years ago
A jar contains 12 red marbles numbered 1 to 12 and 6 blue marbles numbered 1 to 6. A marble is drawn at random from the jar. Fin
lora16 [44]

Answer:

(a)P(Red)=\dfrac{2}{3}\\(b)P(Odd) =\dfrac{1}{2}\\(c)P(\text{Red or Odd Numbered})=\dfrac{5}{6}\\(d)P(\text{Blue or Even Numbered})=\dfrac{2}{3}

Step-by-step explanation:

Number of Red Marbles{1,2,3,4,5,6,7,8,9,10,11,12},n(R)=12

Number of Blue Marbles{1,2,3,4,5,6},n(B)=6

Total Number of Marbles, n(S)=6+12=18

(a)Probability that the Marble is Red

P(R)=\dfrac{n(R)}{n(S)} =\dfrac{12}{18} =\dfrac{2}{3}

(b)Probability that the marble is odd-numbered.

Number of Odd-Numbered Balls, n(O)=9

P(Odd)=\dfrac{n(O)}{n(S)} =\dfrac{9}{18} =\dfrac{1}{2}

(c)Probability that the marble is red or odd-numbered.

n(Red)=12

n(Odd Numbered marbles)=9

n(Red and Odd Numbered Marbles)=6

P(\text{Red or Odd Numbered})=P(Red)+P(Odd\:Numbered)-P(\text{Red and Odd Numbered)}\\=\dfrac{12}{18} +\dfrac{9}{18}-\dfrac{6}{18}  =\dfrac{15}{18}\\P(\text{Red or Odd Numbered})=\dfrac{5}{6}(d)Probability that the marble is blue or even-numbered.

n(Blue)=6

n(Even Numbered marbles)=9

n(Blue and Even Numbered Marbles)=3

P(\text{Blue or Even Numbered})=P(Blue)+P(Even\:Numbered)-P(\text{Blue and Even Numbered)}\\=\dfrac{6}{18} +\dfrac{9}{18}-\dfrac{3}{18}  =\dfrac{12}{18}\\P(\text{Blue or Even Numbered})=\dfrac{2}{3}

5 0
3 years ago
PLEASE HELP ME ASAP! Is my answer correct?
Rudik [331]
Yes it is ABATE ok it is correct
6 0
3 years ago
Read 2 more answers
Can someone please help me
zhannawk [14.2K]

Answer:

6n-5=43

   +5 +5

6n=48

/6    /6

n=8

Step-by-step explanation:

i hope this helps :)

5 0
3 years ago
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