All categories

3 years ago

Multiply. Write your answer as a fraction in simplest form. −3/5 × 8/6=

Mathematics

2 answers:

user100 [1]3 years ago

7 0

I think the answer is -4/5

Kryger [21]3 years ago

3 0

- 3/5*8/6 = - 4/5 OR -0.8

You might be interested in

The following statement describes the number of marbles, n, in a bag. Ten less than eight times the number of marbles is greater

eimsori [14]

The number of marbles is greater than or equal to 12.

The inequality would be:

8n-10≥6n+14

We need to gather all of the variables on one side, so we will subtract 6n from both sides:

8n-10-6n≥6n+14-6n
2n-10≥14

Now we will cancel the 10 by adding it:
2n-10+10≥14+10
2n≥24

Divide both sides by 2:
2n/2 ≥ 24/2
n≥12

6 0

3 years ago

Question #5

erastova [34]

X=9 how to solve: 72+48=8x+48
72=8x 8*9=72

4 0

3 years ago

Mr.jonson sells erasers for $3 each.He sold 96 erasers last week and he sold 204 erasers this week.About how much more money did

7nadin3 [17]

Answer: About $300

Step-by-step explanation:

1. To solve this problem and estimate how much more money Mr. Johnson made this week (which you can call x) you must apply the proccedure shown below:

- Round the number of erasers sold:

96 erasers≈100 erasers

204 erasers≈200 erasers

- The amount of money made last week is:

$\$3*100=300\$$

- The amount of money made this week is:

$\$3*200=600\$$

- Now, you must subtract the quantities shown above, then you obtain:

$m=\$600-\$300\\m=\$300$

7 0

4 years ago

Given A = {a, b, c}, how many subsets does A have including ∅?<br><br> 4<br> 7<br> 8

Minchanka [31]

Answer:

8 is the answer

hope this helps you.

6 0

3 years ago

The data set shows how many points Mark scored in each basketball game he played this season.

algol [13]

Answer:

Kindly check attached picture

Step-by-step explanation:

Given the data :

1,4,4,5,5,7,8,8,10,11,11,11,14,15,16

The median (Q2) :

0.5(n + 1)th value

n = number of observations = 15

0.5(15 + 1)th value = 0.5(16) = 8th observation = 8

Q3:

0.75(n+1)th value = 0.75(16) = 12th observation = 11

Q1 :

0.25(n+1)th value = 0.25(16) = 4th observation = 5

Interquartile range (IQR) = (Q3 - Q1) :

11 - 5 = 6

MINIMUM VALUE IN DATASET = 1

MAXIMUM VALUE IN DATASET = 16

5 0

4 years ago