A video is a recording of a motion, or television program for playing through a television. A camcorder is a device or gadget that is used to record a video. audio is the sounds that we hear and mix media is a tool used to edit the video.
The three basic logical operators recognized by the most search engines are AND, OR and NOT. They are known as Boolean operators. <span>You
can use Boolean operators in keywords on the internet in both advanced and customs
searches on many search engines.</span>
[B] True.
In something like Microsoft Publisher, you are able to go to Insert -> Table, and specify the dimensions for the table you want.
Answer:
"Affordance" is the correct answer.
Explanation:
- The performance or properties of such an entity that determines its possible applications which makes it abundantly clear how everything could and should always be used people are sitting or standing on something like a chair as it is very apparent.
- Users are allowed to experience conceptions without thinking about how to make use of other objects.
Answer:
This question is incomplete, here is the complete question;
If a stop-and-wait protocol is used, what is the fraction of time, in seconds, that the sender is busy sending bits into the channel (the utilization), given that the round-trip-time (RTT) for a router is 20ms when sending 2000 Byte packets ( a byte is 8 bits) at 500Mega bits per second (Mbps)? Answer to the nearest tenth of a microsecond. Recall that the formula for utilization U is L/R / (L/R + RTT). Be careful of your units. Provide the answer in microseconds with one decimal place. Do not label your answer with the units, just provide the number .
Explanation:
The Answer to the question is given with proper step by step solution.
Given that : the round-trip-time (RTT in abbreviation) = 20ms = 0.02 micro seconds
L = 2000
Byte = 2000*8
bits = 16000 bits
R = 500Mbps = 500*106 bps
Now,calculate L/R = 16000 / 500*106
= 32 / 106
= 32 micro seconds
The Utilization (U) = fraction when the time sender is busy sending
= (L/R) / (L/R + RTT)
= (32) / (32 + 0.02)
= 32 / 32.02
= 0.99937539 seconds
= 999375.39 micro seconds
= 999375.4 (nearest tenth)