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3 years ago

Which equation is equivalent to log3(2x4 + 8x3) – 3log3x = 2log3x?

Mathematics

2 answers:

Tamiku [17]3 years ago

6 0

Answer:

log3(2x+8)=log3x^2

Step-by-step explanation:

vlada-n [284]3 years ago

6 0

Pt1 C

pt2.

x= -2 and x=4

pt3

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In which quadrant do the points have negative x-coordinates and negative y-coordinates?

posledela

The answer is Quadrant III.

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3 years ago

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Find the distance between the two points (-2, -6) (3, 9)

sesenic [268]

Hope this will help u...:)

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2 years ago

Write a word phrase for the following algebraic expression 0.5 (y+3.3)

AlladinOne [14]

0.5(y + 3.3)

The product of 0.5 and the sum of y and 3.3.
0.5 times the sum of y and 3.3

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3 years ago

Find the perimeter of this semi-circle with diameter, d = 18cm. Give your answer as an expression in terms of pi.

OLga [1]

Answer:

The perimeter of the given semi-circle in terms of $\pi$ is

$P=9\pi$ cm

Step-by-step explanation:

Given that the diameter of the semi-circle is 18cm

That is d=18cm

Therefore radius $r=\frac{d}{2}$

$r=\frac{18}{2}$

Therefore radius r=9cm

To find the perimeter of the semi-circle :

perimeter of the semi-circle $P=\pi r$

$P=\pi\times 9$ cm (where r=9 cm )

$P=9\pi$ cm

The perimeter of the given semi-circle in terms of $\pi$ is

$P=9\pi$ cm

8 0

2 years ago

After your yearly checkup, the doctor has some bad news and some good news. The bad news is that you tested positive for a serio

Maru [420]

Answer:

0.009804

Step-by-step explanation:

We are given;

probability of testing positive given that you have the disease is 0.99

Also, probability of not testing positive and not having the disease is 0.99

We are also told that it is a rare disease and so strikes only 1 in 1000 people = 0.0001

Let's denote positive test by T+, negative test by T¯, having the disease by D+, not having the disease by D¯.

So, we can now denote all the values in probability we have written earlier.

Thus:

P(T+ | D+) = 0.99

P(T¯ | D¯) = 0.99

P(D+) = 0.0001

Thus, P(D¯) = 1 - P(D+) = 1 - 0.0001 = 0.9999

Now, let's find probability of testing positive;

P(T+) = (P(T+ | D+) × P(D+)) + (P(T+ | D¯) × P(D¯))

Now, (P(T+ | D¯) is not given but by inspection, we can infer from the values given that it is 0.01

Thus;

P(T+) = (0.99 × 0.0001) + (0.01 × 0.9999)

P(T+) = 0.010098

Chances that one has the disease would be gotten from Baye's theorem;

P(D+ | T+) = (P(T+ | D+) × P(D+))/P(T+) = (0.99 × 0.0001)/0.010098 = 0.009804

7 0

3 years ago