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Juliette [100K]
2 years ago
13

Persons taking a 30-hour review course to prepare for a standardized excam averago a score of 620 on that exam. Persons taking a

70-hour review course average a score of 809. Find a linear function, S(t), which fits this data, and which
expresses score as a function of time. Use this function to predict an average score for persons taking a 42-hour review course. Do not round until the final answer. Then round to the nearest tenth as needed.
Mathematics
1 answer:
wolverine [178]2 years ago
6 0

Answer:

S(t) = 4.725t + 478.25

S(t) = 4.725(42)+478.25

S(t) = 676.7

Step-by-step explanation:

In the question, score is a function of time, that means time is the x-axis, while score is the y-axis.

Order the pairs to get:

(30,620) and (70, 809)

With these values, you use the the equation \frac{x2-x1}{y2-y1} to get the slope m.

\frac{70-30}{809-620}  = 4.725

Use this equation and input any ordered pair to get the final function.

y-y1 = m(x-x1)

y-620 = 4.725x-141.75

y = 4.725x + 478.25

Replace x with t and y with S(t) to fit the x & y axis of the question.

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8 0
3 years ago
A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters
natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that p = 0.7

20 eligible voters were randomly selected from the population of all eligible voters.

This means that n = 20

What is the probability that fewer than 11 of them will vote?

This is:

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308

P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120

P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039

P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010

P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002

P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479

0.0479 = 4.79% probability that fewer than 11 of them will vote

8 0
3 years ago
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