11. You’ve done it correctly
12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2
13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution
14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath
15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4
Hope this helped :)
The rule would be : 3^x, where x starts at 0.
3^0 is 1,
3^1 is 3, because 3 one time is 3.
3^2 is 9, because 3x3 is 9.
3^3 is 27, because 3x3x3 is 27
Answer: 3^x
Answer:
4
Step-by-step explanation:
The question is asking what the output is when you input -6 for x. You get the point (-6,4)
Answer:
12x +14
1.) divide both sides but 12 to get the variable alone
12x becomes just the variable x
14 is now 1.16 with the 6 having a line above it showing its repeating.
x = 1.16 repeated
Answer:
y=17
Step-by-step explanation:
So the shape is a square, which means 1 is equal to 90 degrees. So, 4y+22=90
When you solve, you get 17:
4y=68
y=17
