Find the lcm of 8 and 56

2 points

miskamm [114]

The x - intercept of 5x - 3y = 15 is (3, 0)

The y -intercept of 5x - 3y = 15 is (0, -5)

<h3>Solution:</h3>

Given equation is 5x - 3y = 15

To find: x - intercept and y -intercept

The x intercept is the point where the line crosses the x axis. At this point y = 0

The y intercept is the point where the line crosses the y axis. At this point x = 0.

Finding x - intercept:

To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x

So put y = 0 in given equation

5x - 3(0) = 15

5x = 15

x = 3

So the x - intercept is (3, 0)

Finding y - intercept:

To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y

So put x = 0 in given equation

5(0) - 3y = 15

-3y = 15

y = -5

So the y - intercept is (0, -5)

5 0

3 years ago

X-intercept and y-intercepts og y=x^2-3

Rufina [12.5K]

Answer:

Part 1) The y-intercept is the point $(0,-3)$

Part 2) The x-intercepts are the points $(-\sqrt{3},0)\ and\ (\sqrt{3},0)$

Step-by-step explanation:

we have

$y=x^{2}-3$

This is a vertical parabola open upward

step 1

Find the y-intercept

we know that

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

$y=(0)^{2}-3$

$y=-3$

The y-intercept is the point (0,-3)

step 2

Find the x-intercepts

we know that

The x-intercept is the value of x when the value of y is equal to zero

so

For y=0

$x^{2}-3=0$

solve for x

Adds 3 both sides

$x^{2}-3+3=0+3$

$x^{2}=3$

take square root both sides

$x=(+/-)\sqrt{3}$

so

The x-intercepts are the points $(-\sqrt{3},0)\ and\ (\sqrt{3},0)$

3 0

3 years ago

A soccer field is a rectangle 100 meters wide and 130 meters long. The coach asks players run from one corner to the other corne

velikii [3]

Answer:

164.0123 meters

Step-by-step explanation:

√(130^2 + 100^2)

the diagonal of rectangle is the hypotenus

7 0

2 years ago

The answer is D. Because 1 3/7=1.42

ladessa [460]

Thank you for the answer

3 0

3 years ago

After transforming f(x) = 2x² +4x + 3 into vertex form, the vertex is easily identifiable. Which ordered pair is the vertex?

jolli1 [7]

The vertex is $(-1,1)$

Explanation:

The equation is $f(x)=2x^{2} +4x+3$

To find the vertex, we need the equation in the form of $f(x)=a (x-h)^{2}+k$

Dividing each term by 2 in the equation $f(x)=2x^{2} +4x+3$

$f(x)=2(x^{2} +2x+\frac{3}{2} )$

Now, completing the square by adding and subtracting 1, we get,

$f(x)=2(x^{2} +2x+1-1+\frac{3}{2} )$

The first three terms can be written as $(x+1)^{2}$ ,

$f(x)=2[(x+1)^{2}+\frac{1}{2} ]$

Multiplying 2 into the bracket, we get,

$f(x)=2(x+1)^{2} +1$

This equation is of the form $f(x)=a (x-h)^{2}+k$

Now, we shall find the vertex $(h,k)$

Thus, $h=-1$ and $k=1$

Thus, the vertex is $(-1,1)$

7 0

3 years ago