Assuming she got 2kg of oranges at $1.99/kg, 3kg of bananas at $2.75/kg and 5kg of apples at $2.15/kg...
For 2kg of oranges she spent
1.99×2= $3.98
For 3kg of bananas she spent
2.75×3= $8.25
For 5kg of apples she spent
2.15×5= $10.75
3.98+8.25+10.75= $22.98
She spent $22.98 in total.
30-22.98= $7.02
She received $7.02 in change.
Answer:
6028.8
Step-by-step explanation:
Answer:
$6.16
Step-by-step explanation:
Total amount paid = $107.78
Total time worked = 3 and half hours for 5 days
![=3\dfrac{1}{2}\cdot 5\\ \\=\dfrac{7}{2}\cdot 5\\ \\=\dfrac{35}{2} \ hours](https://tex.z-dn.net/?f=%3D3%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%205%5C%5C%20%5C%5C%3D%5Cdfrac%7B7%7D%7B2%7D%5Ccdot%205%5C%5C%20%5C%5C%3D%5Cdfrac%7B35%7D%7B2%7D%20%5C%20hours)
Amount earned per hour
![=\$107.78:\dfrac{35}{2}\\ \\=\$107.78\cdot \dfrac{2}{35}\\ \\\approx \$6.16](https://tex.z-dn.net/?f=%3D%5C%24107.78%3A%5Cdfrac%7B35%7D%7B2%7D%5C%5C%20%5C%5C%3D%5C%24107.78%5Ccdot%20%5Cdfrac%7B2%7D%7B35%7D%5C%5C%20%5C%5C%5Capprox%20%5C%246.16)
Yes you can use this equation to solve this problem
Answer:
![cos(\theta)=(+/-)0.84](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%28%2B%2F-%290.84)
Step-by-step explanation:
we know that
----> by trigonometric identity
we have
![sin(\theta)=0.55](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D0.55)
substitute
![(0.55)^2+cos^2(\theta)=1](https://tex.z-dn.net/?f=%280.55%29%5E2%2Bcos%5E2%28%5Ctheta%29%3D1)
![cos^2(\theta)=1-(0.55)^2](https://tex.z-dn.net/?f=cos%5E2%28%5Ctheta%29%3D1-%280.55%29%5E2)
![cos^2(\theta)=0.6975](https://tex.z-dn.net/?f=cos%5E2%28%5Ctheta%29%3D0.6975)
![cos(\theta)=(+/-)\sqrt{0.6975}](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%28%2B%2F-%29%5Csqrt%7B0.6975%7D)
![cos(\theta)=(+/-)0.84](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%28%2B%2F-%290.84)
Remember that
If the sine of angle theta is positive, then the angle theta lie on the I Quadrant or II Quadrant
therefore
If the angle theta is on the I Quadrant the cosine will be positive
If the angle theta is on the II Quadrant the cosine will be negative